All categories

3 years ago

2×10 to the six power times 0.00009

Mathematics

1 answer:

const2013 [10]3 years ago

5 0

Answer:

5760

Step-by-step explanation:

(2 * 10)^6 * 0.00009

First solve inside the parentheses

20^6 * 0.00009

Then solve powers

64'000'000 * 0.00009

Solve multiplications

5760

This answer might not be the one that is asked for, as the writing is kind of vague, but if you turn this inn with explanation you will not get it wrong

You might be interested in

The perimeter of the triangle at the right is 22.6 in. What is the value of n?

blagie [28]

Answer:

A. 3.5

Step-by-step explanation:

The perimeter is just the sum of all of the side lengths. The sides of this triangle are n inches, (n + 5.2) inches, and (2n + 3.4) inches.

So, your equation is n + n + 5.2 + 2n + 3.4 = 22.6 inches.

You can combine like terms (adding together all of the n's and all of the numbers) to simplify your equation to 4n + 8.6 = 22.6 inches.

Subtract 8.6 from both sides of the equation to get 4n = 14, and divide both sides by 4 to get n = 3.5.

Hope this helps! :)

8 0

2 years ago

WILL GIVE A BRAINLEST AND 50PTS FOR CORRECT ANSWER THANXS!!!!!!!!!!!!!!!!!!!

DochEvi [55]

D. (xy2 + 3z14)(x2y4 – 3xy2z14 + 9z28

3 0

3 years ago

Read 2 more answers

Find the area of a triangular prism

saveliy_v [14]

In order to calculate the area of a triangular prism, You can use the formula,

Area = 1/2 * a * c * h

Hope this helps!

7 0

3 years ago

Select the correct answer.

Rina8888 [55]

A - actuary...........that is the answer

6 0

3 years ago

Read 2 more answers

A university dean is interested in determining the proportion of students who receive some sort of financial aid. Rather than ex

Olenka [21]

Answer:

The 90% confidence interval that estimate the true proportion of students who receive financial aid is

$0.533 < p < 0.64$

$n = 1789$

Step-by-step explanation:

Considering question a

From the question we are told that

The sample size is n = 200

The number of student that receives financial aid is $k = 118$

Generally the sample proportion is

$\^ p = \frac{k}{n}$

=> $\^ p = \frac{118}{200}$

=> $\^ p = 0.59$

From the question we are told the confidence level is 90% , hence the level of significance is

$\alpha = (100 - 90 ) \%$

=> $\alpha = 0.10$

Generally from the normal distribution table the critical value of $\frac{\alpha }{2}$ is

$Z_{\frac{\alpha }{2} } = 1.645$

Generally the margin of error is mathematically represented as

$E = Z_{\frac{\alpha }{2} } * \sqrt{\frac{\^ p (1- \^ p)}{n} }$

=> $E = 1.645 * \sqrt{\frac{0.59 (1- 0.59)}{200} }$

=> $E = 0.057$

Generally 90% confidence interval is mathematically represented as

$\^ p -E < p < \^ p +E$

=> $0.533 < p < 0.64$

Considering question b

From the question we are told that

The margin of error is E = 0.03

From the question we are told the confidence level is 99% , hence the level of significance is

$\alpha = (100 - 99 ) \%$

=> $\alpha = 0.01$

Generally from the normal distribution table the critical value of is

$Z_{\frac{\alpha }{2} } = 2.58$

Generally the sample size is mathematically represented as

$[\frac{Z_{\frac{\alpha }{2} }}{E} ]^2 * \^ p (1 - \^ p )$

=> $n = [\frac{2.58}{0.03} ]^2 * 0.59 (1 - 0.59 )$

=> $n = 1789$

8 0

3 years ago