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3 years ago

PLEASE HELP THIS IS MY FINAL

Mathematics

2 answers:

Over [174]3 years ago

7 0

Answer:

Cross products

Aleksandr [31]3 years ago

6 0

Cross products
I think because I would usually call them the extreme and mean but multiplying them is cross product :)

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Help me plz............................................... i need help

Luda [366]

the answer is 21+2=(32-14)

8 0

3 years ago

You have 15 milliliters of a drink that contains 15% milk. How many millimeters of a drink containing 63% milk needs to be added

Igoryamba

Answer:

4 ml of the 63% milk drink

Step-by-step explanation:

Multiplying 15 ml by 0.15 results in 2.25 ml, the amount of whole milk in the drink. Let m represent the number of ml of a drink that is 63% milk.

The final amount of milk drink that is to be 45% milk will be 15 ml + m, and the amount of whole milk contained in this drink will be 0.45(15 + m).

Then:

0.15(15 ml) + 0.63(m) = 0.45(15 + m), where m is to be in milliliters.

2.25 + 0.63m = 6.75 + 0.45m

First: consolidate the m terms on the left. 0.63m less 0.45m yields 18 m; then we have:

2.25 + 18m = 6.75, or

18 m = 4.50, or m = 4 ml.

In conclusion: adding 4 ml of that 63% milk drink to the initial 15 ml of 15% milk will result in (15 ml + 4 ml) of a 45% milk drink.

8 0

3 years ago

<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B4%7D%7B5%20%7D%20%20%5Ctimes%20%20%5Cfrac%7B3%7D%7B9%7D%20%2B%20%20%5Cfrac%7B2%7D

Reptile [31]

Answer:

$\frac{14}{15}$

Step-by-step explanation:

$\frac{4}{5}$ × $\frac{3}{9}$ + $\frac{2}{3}$ ( firstly, multiply the 2 fractions together )

= $\frac{12}{45}$ + $\frac{2}{3}$

= $\frac{4}{15}$ + $\frac{2}{3}$

= $\frac{4}{15}$ + $\frac{2(5)}{3(5)}$

= $\frac{4}{15}$ + $\frac{10}{15}$

= $\frac{14}{15}$

7 0

3 years ago

The waiting times at a certain bank are normally distributed with a mean waiting time of 3.7 minutes and a standard deviation of

muminat

Answer:

From the given options we can say the correct answer is d.) 6.3

Step-by-step explanation:

The waiting times at the bank are given to be normally distributed.

The mean of the waiting time is given as = 3.7 minutes

The given standard deviation is = 1.4 minutes

It is required to find the waiting time at the 97th percentile.

So we are required to find the time which can be said to be the waiting time which occurs with 97 % probability.

Let the time required be designated as y.

Therefore we can write p(X < y) = 0.97 (where 0.97 means the 97th percentile)

This is a left tailed test.

Using the formula from MSEXCEL to find y we get

y = NORMINV(0.97, 3.7, 1.4) = 6.333.

The other approach would to find the Z value corresponding to the probability value from the Z Table

The Z value for a probability of 0.97 gives us Z = 1.881 .

Therefore $\frac{y - 3.7}{1.4} = 1.881$ . Therefore y = (1.881 × 1.4) + 3.7 = 6.33

Therefore from the given options we can say the correct answer is d.) 6.3

7 0

3 years ago

Answer Choices:

astra-53 [7]

The answer is D. 60'. You add both angles together, then subtract them from 180.
60+70=120
180-120=60

4 0

3 years ago