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lapo4ka [179]
3 years ago
9

Christian sold tickets to game. Good seats were $5 each poor seats cost $2 each. 210 people attended and paid $660. Write a syst

em of linear equations that can be used to find how many good seats and how many poor seats were sold. How many of each type of seat were sold?
Mathematics
1 answer:
nignag [31]3 years ago
6 0
5(g) + 2(p) = 660
-2(g+p=210)
5g+2p=660
-2g-2p=-420
3g/3=240/3
g=80

g+p=210
80+p=210
-80. -80
P=130
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An online data base charges $25 an hour during the day and $12.50 an hour at night. If a research company paid $250 for 12 hours
Firdavs [7]

Answer

Find out the  which system of equations could be used to determine the number of hours charged at the day rate (d) and at the night rate (n) .

To proof

As given in the question

Let us assume that the number of hours charged at the day rate = d

Let us assume that the number of hours charged at the night rate = n

An online data base charges $25 an hour during the day and $12.50 an hour at night. If a research company paid $250 for 12 hours of use.

Total working hour in a company including day and night be  12 hours .

than the equation become in the form

d + n = 12

also

An online data base charges $25 an hour during the day

$12.50 an hour at night.

If a research company paid $250 for 12 hours of use.

than the equation becomes

25d + 12.50n = 250

than the two equation are

d + n = 12 , 25d + 12.50n = 250

multiply first by 25 and subtracted  from 25d + 12.50n = 250

25d - 25d + 12.50n - 25n = 250 - 300

12.5 n = 50

n = \frac{50}{12.5}

n = 4hours

put this in the d + n = 12

d + 4 =12

d = 12-4

d = 8 hours

Therefore the number of hours charged at the day rate  is 8 hours  and at the night rate is  4hours .

Hence proved



4 0
4 years ago
Y=(2x-3)^5(2-x^4)^3 differentiate the function please
BARSIC [14]
\bf y=(2x-3)^5(2-x^4)^3\\\\
-------------------------------\\\\
\cfrac{dy}{dx}=\stackrel{\textit{product rule}}{[5(2x-3)^4\cdot 2(2-x^4)3]~~+~~[(2x-3)^5[3(2-x^4)^2(-4x^3)]]}
\\\\\\
\cfrac{dy}{dx}=10(2x-3)^4(2-x^4)^3~~-~~12x^3(2x-3)^5(2-x^4)^2
\\\\\\
\cfrac{dy}{dx}=\stackrel{\textit{common factor}}{2(2x-3)^4(2-x^4)^2}~[5(2-x^4)-6x^3(2x-3)]
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\cfrac{dy}{dx}=2(2x-3)^4(2-x^4)^2~[10-5x^4-12x^4+18x^3]
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\cfrac{dy}{dx}=2(2x-3)^4(2-x^4)^2(10-17x^4+18x^3)
5 0
3 years ago
No links
ludmilkaskok [199]

Answer:

2/5

Step-by-step explanation:

There's 5 jellybeans in the bag total and of the five, 2 of them are red, so the probability that Cynthia gives him 2 reds is 2/5.

5 0
3 years ago
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What is this in simplest form?
Norma-Jean [14]

Answer:

1/4

Step-by-step explanation

you divide 25 divided by 25 the also divide 100 divided by 25 and u get 1/4

7 0
3 years ago
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Find the cardinality of the set B = { 5, 6, 7, … , 100}
vaieri [72.5K]

The cardinality of the set B is given to be 96.

<h3>What is the cardinality of a set?</h3>

This is the term that is used to refer to the number of elements that a given set can be said to contain.

This is a set that has numbers that ranges from 5 to 100, this tells us that the numbers 1, 2, 3, 4 are excluded from the set.

Hence the total numbers excluded is 4. 100 - 4 = 96

Therefore from 5 to 100, the total 9 and the cardinality of the set B is 96.

Read more on the cardinality of a set here: brainly.com/question/23976339

#SPJ1

3 0
1 year ago
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