Answer:
x < 2
Step-by-step explanation:
We're going to solve this just like we would an equation, but with just one little twist. First, let's add 1/3 to both sides.
5/6x - 1/3 > 1 1/3
5/6x > 1 2/3
First, let's turn 1 2/3 into an improper fraction to make it easier to work with. Multiply the big number by the denominator, then add the numerator.
1 x 3 + 2 = 5
1 2/3 = 5/3
Now, multiply 5/3 by 2/2 to get 6 as the denominator. This works because 2/2 simplifies to 1 and therefore does not change the value of the fraction.
5 x 2 = 10
3 x 2 = 6
5/3 = 10/6
Now divide both sides by 5/6. Because they both have the same denominator, we can cancel the denominator out and just divide 5x/5 and 10/5.
5/6x > 10/6
5x > 10
x > 2
Wait! We don't have the correct answer just yet. Whenever you divide an inequality, you have to flip the inequality sign.
x < 2
Now <em>there's</em> our final answer.
Answer:
y = 20*4^x
Step-by-step explanation:
to find the value of the constants a and b, we just need to use the points given in the equation and solve the system of equations:
point (0,20): x = 0 and y = 20:
20 = a*b^0 = a*1 = a
a = 20
point (2,320): x = 2 and y = 320
320 = 20 * b^2
b^2 = 16
|b| = 4
b = 4 or b = -4
So we have two exponencial equations that pass through these points:
y = 20*4^x and y = 20*(-4)^x
As the questions asks for just one equation, we can answer y = 20*4^x
Answer:The answer is 2 if you use a calculator.
Step-by-step explanation:
In the given image, 
is 5. The correct option is the first option 5
<h3>Matrix notation</h3>
From the question, we are to determine which entry in the given matrix represents
NOTE: For any entry denoted as 
, it represents the entry in the <em>m</em>-th row and <em>n</em>-th column.
Thus,
represents the entry in the 2nd row and 3rd column.
In the given image, the entry in the 2nd row and 3rd column is 5.
Hence, in the given image, is 5. The correct option is the first option 5
Learn more on Matrix notation here: brainly.com/question/2382978
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Answer:
A: 0
B: pi/3
E: 5pi/3
Step-by-step explanation:
