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abruzzese [7]
3 years ago
9

A butcher has 8 1 3 pounds of ground beef that will be priced at $4.64 per pound. He divides the meat into 8 equal packages. To

the nearest cent, the price of each package is
Mathematics
1 answer:
yan [13]3 years ago
5 0

Answer:

the answer would be 101

Step-by-step explanation:

Im really sorry if the answer is not right

You might be interested in
If 2/9 of the students in a school are in 6th grade, then how
sveticcg [70]

Answer:

231

Step-by-step explanation:

\frac{2}{9} =\frac{42}{x}

42÷2= 21

9×21= 189

189 students total

42 6th graders

5 0
3 years ago
Read 2 more answers
Find the measures of the numbered angles in each kite.
Vlad [161]

Answer:

x = 19°

y = 31°

Step-by-step explanation:

5x = 7x - 38

2x = 38

x = 19

y = 180 - 54 - 5(19)

y = 31

8 0
3 years ago
WLL GIVE BRAINLIST PLEASE help... i sincerely don't even know where to begin here. ​
Harman [31]

Answer:

y = 5

Step-by-step explanation:

WY is the perpendicular bisector of XZ and so divides ΔWXZ into 2 congruent triangles ΔWXY and ΔWZY

Hence WZ = WX ← corresponding sides, thus

5y - 8 = 2y + 7 ( subtract 2y from both sides )

3y - 8 = 7 ( add 8 to both sides )

3y = 15 ( divide both sides by 3 )

y = 5

4 0
3 years ago
Read 2 more answers
The standard deviation of math test scores at one high school is 16.1. A teacher claims that the standard deviation of the girls
Elanso [62]

Answer:

\chi^2 =\frac{22-1}{259.21} 166.41 =13.482

p_v =P(\chi^2

In order to find the p value we can use the following code in excel:

"=CHISQ.DIST(13.482,21,TRUE)"

If we compare the p value and the significance level provided we see that p_v >\alpha so on this case we have enough evidence in order to FAIL reject the null hypothesis at the significance level provided. And that means that the population deviation is not significantly lower than 16.1 at 1% of significance.

Step-by-step explanation:

Notation and previous concepts

A chi-square test is "used to test if the variance of a population is equal to a specified value. This test can be either a two-sided test or a one-sided test. The two-sided version tests against the alternative that the true variance is either less than or greater than the specified value"

n=22 represent the sample size

\alpha=0.01 represent the confidence level  

s^2 =12.9^2=166.41 represent the sample variance obtained

\sigma^2_0 =16.1^2 =259.21 represent the value that we want to test

Null and alternative hypothesis

On this case we want to check if the population deviation is smaller than 16.1 (that's equivalent to check if the population variance is lower than 259.21:

Null Hypothesis: \sigma^2 \geq 259.21

Alternative hypothesis: \sigma^2

Calculate the statistic  

For this test we can use the following statistic:

\chi^2 =\frac{n-1}{\sigma^2_0} s^2

And this statistic is distributed chi square with n-1 degrees of freedom. We have eveything to replace.

\chi^2 =\frac{22-1}{259.21} 166.41 =13.482

Calculate the p value

In order to calculate the p value we need to have in count the degrees of freedom , on this case 21. And since is a left tailed test the p value would be given by:

p_v =P(\chi^2

In order to find the p value we can use the following code in excel:

"=CHISQ.DIST(13.482,21,TRUE)"

Conclusion

If we compare the p value and the significance level provided we see that p_v >\alpha so on this case we have enough evidence in order to FAIL reject the null hypothesis at the significance level provided. And that means that the population deviation is not significantly lower than 16.1 at 1% of significance.

3 0
3 years ago
What are the variables?
tresset_1 [31]

Answer:

T and R

Step-by-step explanation:

Variables are letters that are a quantity not known yet

5 0
2 years ago
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