If shapes have at least one pair of right angles, they do have one pair of perpendicular sides (True).
Simultaneous Equations:
(3x + 5y = 7)×(-3)
(4x + 3y = 2)×(5)
-9x - 15y = -21
20x+15y =10 (-15y and and+15y cancels out)
11x = -11

=

(11 and 11 cancels out)
x= -1
substitute the x we found into either original expressions
3(-1) + 5y = 7
-3 + 5y = 7
+3 -3+ 5y = 7+ 3
5y = 10

=

(5 and 5 cancels out)
y=2
Check it!
4(-1)+3(2) = 2
-4 + 6 = 2
2 = 2
3(-1) + 5(2) = 7
-3 + 10 = 7
7 = 7
x= -1y= 2
9514 1404 393
Answer:
an = 13 -5(n -1)
Step-by-step explanation:
The "take away 5" rule means the common difference between terms is d=-5. For first term a1=13, the n-th term is ...
an = a1 +d(n -1)
an = 13 -5(n -1)

(3xy^2 4 sqrt 4x^2)
Step-by-step explanation:
<h3>Hope it's helpful to you</h3>