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Sati [7]
3 years ago
12

Which angle’s measure is equal to the sum of the measures of ∠BAC and ∠BCA?

Mathematics
1 answer:
hjlf3 years ago
4 0

Answer: <CBE

Step-by-step explanation:

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98464 rounded to the nearest ten thousand?​
dusya [7]

Answer:

100000

Step-by-step explanation:

4 0
3 years ago
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A line passes through the point (10,-8) and has a slope of negative 3/2Write an equation in slope-intercept form for this line.
zhuklara [117]

Answer:

9383

Step-by-step explanation:

4 0
3 years ago
John has 15 t shirts. 6 black, 3 red, 2 purple, 2 dark blue, 1 light blue, 1 purple
Troyanec [42]

Answer:

ok.... what is the question here....??   ;-;

Step-by-step explanation:

3 0
3 years ago
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Find the equation of the line that passes through point (6, 1) with the x-intercept of 2.
34kurt

<u>Answer:</u>

○ y = \frac{1}{4}x - \frac{1}{2}

<u>Step-by-step explanation:</u>

To find the equation of the line, let's first consider the points whose coordinates we have been given:

• (6, 1)

• (2, 0).

The point (2, 0) is what is called the x-intercept, which is the point where the line crosses the x-axis. This means that at this point, the y-coordinate of the line is 0.

Next, let's calculate the slope (gradient) of the line using the formula:

m = \frac{y_2 - y_1}{x_2 - x_1}

where:

m = gradient,

(x_2, y_2) and (x_1, x_2) = points on the line.

Using the formula:

m = \frac{1 - 0}{6 - 2}

⇒ m =\bf \frac{1}{4}

Finally, now that we have two points on the line as well as the line's slope, we can use the following formula to find the equation of the line:

\boxed{y - y_1 = m(x - x_1)}

You can use any of the points on the line as y_1 and x_1.

Using (2, 0):

y - 0 = \frac{1}{4}( x - 2)

⇒ y = \frac{1}{4}x - \frac{1}{2}

Therefore the equation of the line is y = \frac{1}{4}x - \frac{1}{2}.

Learn more about point-slope form at:

brainly.com/question/15143525

6 0
2 years ago
Assume that a simple random sample has been selected from a normally distributed population. Find the test statistic t.
lawyer [7]

Using the t-distribution, it is found that the p-value of the test is 0.007.

At the null hypothesis, it is <u>tested if the mean lifetime is not greater than 220,000 miles</u>, that is:

H_0: \mu \leq 220000

At the alternative hypothesis, it is <u>tested if the mean lifetime is greater than 220,000 miles</u>, that is:

H_1: \mu > 220000.

We have the <u>standard deviation for the sample</u>, thus, the t-distribution is used. The test statistic is given by:

t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}

The parameters are:

  • \overline{x} is the sample mean.
  • \mu is the value tested at the null hypothesis.
  • s is the standard deviation of the sample.
  • n is the sample size.

For this problem:

\overline{x} = 226450, \mu = 220000, s = 11500, n = 23

Then, the value of the test statistic is:

t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}

t = \frac{226450 - 220000}{\frac{11500}{\sqrt{23}}}

t = 2.69

We have a right-tailed test(test if the mean is greater than a value), with <u>t = 2.69</u> and 23 - 1 = <u>22 df.</u>

Using a t-distribution calculator, the p-value of the test is of 0.007.

A similar problem is given at brainly.com/question/13873630

8 0
2 years ago
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