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3 years ago

Find the area of the equilateral triangle whose sides are 4 yd.

Mathematics

2 answers:

777dan777 [17]3 years ago

6 0

Answer:

Remember:

Triangle area= $\frac{b*h}{2}$

h of equilateral triangle = $\frac{\sqrt{3}}{2}*a$

Step-by-step explanation:

b=4yd

a=4yd

h = $\frac{\sqrt{3}}{2}*a$

h = $\frac{\sqrt{3}}{2}*4yd$

4/2=2

h= $2\sqrt{3} yd$

area= $\frac{b*h}{2}$

area= $\frac{4 yd*2\sqrt{3} yd}{2}$

2/2=1

Finally

area= $4\sqrt{3} yd^2$

suter [353]3 years ago

4 0

Answer:

The first one. 4 times square root of 3.

Step-by-step explanation:

The side of the equilateral triangle that represents the height of the triangle will have a length of because it will be opposite the 60o angle. To calculate the area of the triangle, multiply the base (one side of the equilateral triangle) and the height (the perpendicular bisector) and divide by two.

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Papessa [141]

We performed the following operations:

$f(x)=\sqrt[3]{x}\mapsto g(x)=2\sqrt[3]{x}=2f(x)$

If you multiply the parent function by a constant, you get a vertical stretch if the constant is greater than 1, a vertical compression if the constant is between 0 and 1. In this case the constant is 2, so we have a vertical stretch.

$g(x)=2\sqrt[3]{x}\mapsto h(x)=-2\sqrt[3]{x}=-g(x)$

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