Answer:
its A
Step-by-step explanation:
Use Rule of One: x^1 = x
6 × x^3 + 1 × z/3
Simplify 6 × z^3/3 to 2z^3
2z^3 + 1 × z/3
Simplify 1 × z/3 to z/3
<u>= 2z^3 + z/3</u>
Answer:
x =4 ,y =4 and z =0 is the solution.
Step-by-step explanation:
We shall solve the equations using elimination method
In equation 2 and 3 we can see that coefficient of z in both equations are same with opposite sides , adding equations (2) and (3)
3y+5z = 12
y -5z = 4 adding the equations
___________
4y = 16
dividing both sides by 4
y =
y = 4
Plugging the value of y in equation 2 or equation 3 ,we get
3(4) +5z = 12
12+5z = 12
5z = 12-12 or 5z =0 gives z =0
plugging y =4 and z =0 in equation 1
2x+3(4)+ 0 = 20
2x+12 = 20
2x =20-12
2x = 8
x = 8 divided by 2 gives
x =4
therefore solution of the system is given by
x=4 , y =4 and z =0
Your numbers are 11 and 32
We know that:
a + b = 44
and
a = 3b
If we substitute “3b” in for a in the first equation, we get a numerical value for b
3b + b = 44
4b = 44
b = 11
Then we substitute the numerical value of b to solve for a:
a = 3b
a = 3(11) = 33
Answer:
16,17,18,19
Step-by-step explanation:
one guy guessed. probably using a calculator
another guy took the 4th root of 100,000 and rounded down a number
(a third way started like this
n*(n+1)*(n+2)(n+3)=100000