Answer:
It's a little difficult to see the difference between the finch 1 and finch 2 population lines, but their trends should match those of the food. This answer is assuming the finch 1 population aligns with the seeds line and the finch two population lines up with the fruit line: <u>The finch 1 population has a beak adapted to eating seeds and the finch 2 population has a beak better adapted to eating fruit</u>
Explanation:
Since we are given data for both the food source and the finch population, the answer will most likely reflect that. Therefore eliminating choices A (disease) and C (feathers). Again, this answer is assuming the finch 1 population aligns with the seeds line and the finch two population lines up with the fruit line. The lines for the finch population will match with the availability of food, so less seeds mean less finch 1 and when the amount of seeds rise up you can see the population of finch 1 also rises.
1.) Problem: Diff. Shape of the moon
<span>Hypothisis: earth, sun, n moon locations creates a shadow </span>
<span>Experiment: her experiment </span>
<span>Observation: Researching </span>
<span>Conclusion: she is yet to make one </span>
<span>2.) Size of balls - make them accurate </span>
<span>Research: use multiple sources </span>
<span>The amount of light: keep using the same light</span>
There are so many examples for that in different areas, like organic germanium compounds experiment carried out in our lab recently.
Here's one link: http://www.alfa-chemistry.com/products/organic-germanium-24.htm
The complementary strand on the RNA would be, U-G-G-C-U-C-G-A-A.
Answer:
<u>Part A</u> : 70 secondary oocytes will be formed.
<u>Part B</u> : 70 first polar bodies will be formed.
<u>Part C</u> : 70 ootids will be formed.
Explanation:
During oogenesis growth maturation of a single oogonium produces one primary oogonium.
the primary oogonium then undergoes meiosis -1 and produces one secondary oocyte and first polar body.
The secondary oocyte then undergoes meiosis - 2 and forms an ootid and second polar body.
The ootid then differentiates into the ovum.
As in the above scenario , 70 primary oocytes are present , they undergo meiosis-1 and produces 70 secondary oocytes and 70 first polar bodies. Hence answers of part A and B is 70.
As 70 secondary oocytes are formed , they undergo meiosis -2 and forms 70 ootids which then differentiate in 70 ovums.
