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DerKrebs [107]
3 years ago
12

Between 1932 and 1968, a chemical factory in Japan released mercury-laden wastewater into Minamata Bay. The mercury was modified

to methylmercury by bacteria living in bottom sediments. This resulted in severe mercury poisoning in over 2,000 people. Since people don't eat bottom sediments, what is the best explanation for how toxic levels of mercury ended up in affected people?
Biology
1 answer:
Ipatiy [6.2K]3 years ago
4 0
The toxic still ended up to the affected people because of bioaccumulation. This means that organisms who might have consumed the said mercury was consumed by some larger organisms. These larger organisms were eaten or consumed by human beings. The toxin, in other words, was just passed on to different species. 
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Stolb23 [73]

Answer:

Point 3 for kinetic, points 1 and 5 for potential

Explanation:

There is one point that the ball has the most kinetic energy it is at point 3. Point 3 has the most kinetic energy because it has gained the most speed since it was dropped and it also is right before it starts slowing down from trying to go up again. Points 1 and 5 have the most potential energy. When the ball is at point 1 or 5 it is at its maximum height thus it cannot swing any further, so it stops for a split second and gains a large amount of potential energy before it is released into kinetic energy when it falls back down.

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Explanation:

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A small child gives a plastic frog a big push at the bottom of a slippery 2.0 meter long, 1.0 meter high ramp, starting it with
lesya692 [45]
First, let's find the angle of inclination using the tangent function.

sin θ = opposite/hypotenuse = 1 m/2 m
θ = 30°

Assuming the ramp is frictionless, the force balance is:
F = mgsinθ = ma
Cancelling out m,
a = gsinθ = (9.81 m/s²)(sin 30°) = 4.905 m/s²

Using the equation for rectilinear motion at constant acceleration,
x = v₀t + 0.5at²
2 m = (6 m/s)(t) + 0.5(4.905 m/s²)(t²)
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t = 0.297 seconds

Using the equation for acceleration:
a = (v - v₀)/t
4.905 m/s² = (v - 6 m/s)/0.297 s
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