Answer:
4.26
Explanation:
Let the green-melon parents be Gg, then we expect the cross with the yellow-melon plant gg so as to produce 50% Gg and other 50% of gg offspring. What we observed was that 53 green and a 41 yellow. Based on the total number of 94 offspring , we expected half and a half ratios to be 47 of each color.
Observed(o) Expected(e) (o-e) 
Green-melon plant 53 47 6 36 0.766
Yellow-melon plant 41 47 -6 36 0.766
Therefore the chi-square value is 1.53 which is less than the critical value of 3.84. Therefore, the null hypothesis is accepted.
Answer:
(A)Yes.
Explanation:
Homologous structures provide evidence for common ancestry.
Good Luck
The answer is True.
Hope this helps :)
Answer: DF508 mutation. A Genetic, Hereditary, Autosomal and Recessive Mutation.
Explanation:
Cystic fibrosis (CF) is a recessive autosomal lethal disease, it is most common on Caucasoid populations. Its diagnosis is suggested by the clinical features of chronic obstructive pulmonary disease, persistent pulmonary colonization (particularly with mucoid Pseudomonas strains), meconium ileus, pancreatic insufficiency with or familiarity history of the disease. The FC gene is large, with about 250 Kb of genomic DNA, 27 exons representing about 5% of genomic DNA; encodes a 6.5 kb transcribed mRNA. This mRNA is transcribed into a protein of 1480 amino acid called CFTR (Regulator Transmembrane Conductance Cystic Fibrosis). When a three-base pair deletion, adenosine-thymine-thymine (ATT) identified in the CFTR gene, exon 10, it results in the loss of a single amino acid phenylalanine at position 508 of the protein. This mutation is called DF508; “D” stands for deletion and “F” for phenylalanine amino acid.
