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4 years ago

determine whether the function f9x) x6+10x4-11x2+19 is an even function, an odd function, both, or neither.

Mathematics

1 answer:

nordsb [41]4 years ago

8 0

It’s odd I believe so !

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Serhud [2]

Answer: c

Step-by-step explanation:

5 0

3 years ago

Rachel's garden is square in shape. The length of one side of her garden is 52 feet. What is the area of her garden in square fe

netineya [11]

52^ 2 because this is equal to the area which is 2704 sq ft. So 52 to the second power is your answer. 52 ^2 Hope this helps! :)

3 0

4 years ago

What is the proper equation <br> (-5cd^-4)(2cd^2)^2

mojhsa [17]

Answer:

-20c^3

Step-by-step explanation:

((−5c)(d−4))((2cd2)2)

= −20c3d4 /d4

=-20c^3

7 0

4 years ago

Root 180 times a squared over root 80 times b squared

Studentka2010 [4]

180×80 would give u 14400

3 0

3 years ago

The average height of 20-year-old American women is normally distributed with a mean of 64 inches and standard deviation of 4 in

Murrr4er [49]

Answer:

Probability that average height would be shorter than 63 inches = 0.30854 .

Step-by-step explanation:

We are given that the average height of 20-year-old American women is normally distributed with a mean of 64 inches and standard deviation of 4 inches.

Also, a random sample of 4 women from this population is taken and their average height is computed.

Let X bar = Average height

The z score probability distribution for average height is given by;

Z = $\frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\mu$ = population mean = 64 inches

$\sigma$ = standard deviation = 4 inches

n = sample of women = 4

So, Probability that average height would be shorter than 63 inches is given by = P(X bar < 63 inches)

P(X bar < 63) = P( $\frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } }$ < $\frac{63-64}{\frac{4}{\sqrt{4} } }$ ) = P(Z < -0.5) = 1 - P(Z <= 0.5)

= 1 - 0.69146 = 0.30854

Hence, it is 30.85% likely that average height would be shorter than 63 inches.

7 0

4 years ago