We are given the following data: <span>x = 2t, y = t + 5, -2 ≤ t ≤ 3. The data is valid since there are three unknowns in this problem and that three equations would suffice to answer the problem.
We start with the given </span>-2 ≤ t ≤ 3 then substitute y = t +5 by using the limits of the range:
at t = -2 ; y = -2 + 5 = 3
at t = 3, y = 3+5 = 8
for the second equation
at t = -2 ; x = 2*-2 =-4
at t=3; x = 2*3 = 6
we group the points based on their original corresponding t's
(3,-4) and (8,6) we just have to connect these points along with the internal points in between. The relationship should be linear.
Answer:
1040 tehyimngtumh
Step-by-step explanation:
Apex
Select Is a Function or Is not a Function to correctly classify each relation.
<span><span>Title Is a Function Is not a Function</span><span><span><span><span>{<span><span>(<span>3, 7</span>)</span>,<span>(<span>3, 6</span>)</span>,<span>(<span>5, 4</span>)</span>,<span>(<span>4, 7</span>)</span></span>}</span></span>
</span><span><span><span>{<span><span>(<span>1, 5</span>)</span>,<span>(<span>3, 5</span>)</span>,<span>(<span>4, 6</span>)</span>,<span>(<span>6, 4</span>)</span></span>}</span></span>
</span><span><span><span>{<span><span>(<span>2, 3</span>)</span>,<span>(<span>4, 2</span>)</span>,<span>(<span>4, 6</span>)</span>,<span>(<span>5, 8</span>)</span></span>}</span></span>
</span><span><span><span>{<span><span>(<span>0, 4</span>)</span>,<span>(<span>3, 2</span>)</span>,<span>(<span>4, 2</span>)</span>,<span>(<span>6, 5</span>)</span></span>}</span></span>
</span></span></span>
