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anyanavicka [17]

2 years ago

6

Write 17 1/4 as a decimal

2 answers:

OlgaM077 [116]2 years ago

8 0

17.25

17 is a whole number and 1/4 is 0.25 so add them together and you get 17.25

maksim [4K]2 years ago

3 0

17.25 is your answer.

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A rectangular garden must have a perimeter of 150 feet and an area of at least 1200 square feet. describe the possible lengths o

blagie [28]

The possible lengths of the garden would be all of the common factors of 1200.
1 , 1200
2 , 600
3 , 400
4 , 300
5 , 240
6 , 200
7 , 171.43
8 , 150
9 , 133.33
10 . 120
11 . 109.09
12. 100
13. 92.31
14. 85.71
15. 80
16. 75
17. 70.59
18. 66.67
19. 63.15
20. 60
And so on. (all of the above are in pairs)

5 0

3 years ago

Read 2 more answers

The amount of time it takes Isabella to wait for the bus is continuous and uniformly distributed between 3 minutes and 15 minute

madam [21]

Answer:

33.33% probability that it takes Isabella more than 11 minutes to wait for the bus

Step-by-step explanation:

An uniform probability is a case of probability in which each outcome is equally as likely.

For this situation, we have a lower limit of the distribution that we call a and an upper limit that we call b.

The probability that we find a value X lower than x is given by the following formula.

$P(X \leq x) = \frac{x - a}{b-a}$

For this problem, we have that:

Uniformly distributed between 3 minutes and 15 minutes:

So $a = 3, b = 15$

What is the probability that it takes Isabella more than 11 minutes to wait for the bus?

Either she has to wait 11 or less minutes for the bus, or she has to wait more than 11 minutes. The sum of these probabilities is 1. So

$P(X \leq 11) + P(X > 11) = 1$

We want P(X > 11). So

$P(X > 11) = 1 - P(X \leq 11) = 1 - \frac{11 - 3}{15 - 3} = 0.3333$

33.33% probability that it takes Isabella more than 11 minutes to wait for the bus

4 0

3 years ago

What is equivalent to (x – 8)(x – 6)?

baherus [9]

X^2 - 8x - 6x + 48 i think

6 0

2 years ago

A student on a piano stool rotates freely with an angular speed of 2.85 rev/s . The student holds a 1.50 kg mass in each outstre

Vlad1618 [11]

Answer:r'=0.327 m

Step-by-step explanation:

Given

$N=2.85 rev/s$

angular velocity $\omega =2\pi N=17.90 rad/s$

mass of objects $m=1.5 kg$

distance of objects from stool $r_1=0.789 m$

Combined moment of inertia of stool and student $=5.53 kg.m^2$

Now student pull off his hands so as to increase its speed to 3.60 rev/s

$\omega _2=2\pi N_2$

$\omega _2=2\pi 3.6=22.62 rad/s$

Initial moment of inertia of two masses $I_0=2mr_^2$

$I_0=2\times 1.5\times (0.789)^2=1.867$

After Pulling off hands so that r' is the distance of masses from stool

$I_0'=2\times 1.5\times (r')^2$

Conserving angular momentum

$I_1\omega =I_2\omega _2$

$(5.53+1.867)\cdot 17.90=(5.53+I_o')\cdot 22.62$

$I_0'=1.397\times 0.791$

$I_0'=5.851$

$5.53+2\times 1.5\times (r')^2=5.851$

$2\times 1.5\times (r')^2=0.321$

$r'^2=0.107009$

$r'=0.327 m$

7 0

3 years ago

Problem Page Customers of a phone company can choose between two service plans for long distance calls. The first plan has a $16

lozanna [386]

If their call lasts 11 minutes the cost will be the same

7 0

3 years ago