You can flip a coin, heads can be true and tales can be false.
The minimum value for |x+5| is 0, so the minimum for f(x) is 0-8=-8.
There is no maximum for |x+5|, so neither does f(x).
Therefore the range of f(x)=|x+5|-8 is [-8,+inf) in interval notation, or
from -8 to infinity in words.
Answer:
See below for step-by-step proof.
Step-by-step explanation:

























Answer:
Step-by-step explanation:
