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stiv31 [10]
2 years ago
15

Determine the stopping distances for an automobile going a constant initial speed of 95 km/h and human reaction time of 0.40 s:

(a) for an acceleration a= -3.0 m/s^2; (b) for a = -6.0 m/s2.
Mathematics
1 answer:
Sindrei [870]2 years ago
7 0

Answer:

aaa

Step-by-step explanation:

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7 0
3 years ago
–3.4 + (–8 + 2) = [ ? + (–8)] + 2<br><br> whats the missing number
Ilia_Sergeevich [38]
I suppose what makes this question annoying is that there is the question mark so what i'll do first is substitute the question mark with x. also, there are annoying parenthesis so we'll first eliminate the ones we don't need. now we just have to solve for x. -3.4 + (-8 + 2) = (x + (-8)) + 2 adding a negative number is subtracting that number so x + (-8) = x - 8 -3.4 + 2 - 8 = x - 8 + 2 -3.4 -6 = x - 6 x = -3.4 make sure you are aware that the negative sign belongs to the number after it so -2 + 4 is not -(2+4) = -6 but rather 4 - 2 = 2. let me know if you have any questions!
7 0
3 years ago
Find and simplify the difference quotient of the​ form, <img src="https://tex.z-dn.net/?f=%5Cfrac%7Bf%28x%2Bh%29-f%28x%29%7D%7Bh
Anastasy [175]

With f(x)=-10x+9, we have

f(x+h) = -10(x+h) + 9 = -10x + 9 - 10h

Then the difference quotient is

\dfrac{f(x+h)-f(x)}h = \dfrac{(-10x+9-10h)-(-10x+9)}h = \dfrac{-10h}h = -10

since <em>h</em> ≠ 0.

7 0
3 years ago
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