In AEFG, F = 61 inches, ZF=79º and ZG=34°. Find the length of g, to the nearest 10th of an inch.

Mathematics

1 answer:

DENIUS [597]3 years ago

7 0

Answer:

g ≈ 34.7 in

Step-by-step explanation:

The law of sines is useful for this:

f/sin(F) = g/sin(G)

Multiplying by sin(G), we have ...

g = f·sin(G)/sin(F) = (61 in)·sin(34°)/sin(79°)

g ≈ 34.7 in

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A trough has ends shaped like isosceles triangles, with width 5 m and height 7 m, and the trough is 12 m long. Water is being pu

Svet_ta [14]

Answer:

$\dfrac{dh}{dt}=21 \text{m/min}$

the rate of change of height when the water is 1 meter deep is 21 m/min

Step-by-step explanation:

First we need to find the volume of the trough given its dimensions and shape: (it has a prism shape so we can directly use that formula OR we can multiply the area of its triangular face with the length of the trough)

$V = \dfrac{1}{2}(bh)\times L$

here L is a constant since that won't change as the water is being filled in the trough, however 'b' and 'h' will be changing. The equation has two independent variables and we need to convert this equation so it is only dependent on 'h' (the height of the water).

As its an isosceles triangle we can find a relationship between b and h. the ratio between the b and h will be always be the same:

$\dfrac{b}{h} = \dfrac{5}{7}$