Answer with explanation:
For, a Matrix A , having eigenvector 'v' has eigenvalue =2
The order of matrix is not given.
It has one eigenvalue it means it is of order , 1×1.
→A=[a]
Determinant [a-k I]=0, where k is eigenvalue of the given matrix.
It is given that,
k=2
For, k=2, the matrix [a-2 I] will become singular,that is
→ Determinant |a-2 I|=0
→I=[1]
→a=2
Let , v be the corresponding eigenvector of the given eigenvalue.
→[a-I] v=0
→[2-1] v=[0]
→[v]=[0]
→v=0
Now, corresponding eigenvector(v), when eigenvalue is 2 =0
We have to find solution of the system
→Ax=v
→[2] x=0
→[2 x] =[0]
→x=0, is one solution of the system.
Answer:
f(3) = 9
Step-by-step explanation:
Wherever you see an x on the right, put a 3 in for that x
f(x) = 2x^2 + x - 12
f(3) = 2*(3)^2 + 3 - 12
f(3) = 2*9 + 3 - 12
f(3) = 18 + 3 - 12
f(3) = 9
We call:

as the set of <span>the first 51 consecutive odd positive integers, so:
</span>

Where:





<span>and so on.
In mathematics, a sequence of numbers, such that the difference between two consecutive terms is constant, is called Arithmetic Progression, so:
3-1 = 2
5-3 = 2
7-5 = 2
9-7 = 2 and so on.
Then, the common difference is 2, thus:
</span>

<span>
Then:
</span>

<span>
So, we need to find the sum of the members of the finite series, which is called arithmetic series:
There is a formula for arithmetic series, namely:
</span>

<span>
Therefore, we need to find:
</span>
Given that

, then:

Thus:

Lastly:
Answer:
perimeter = 204m
Step-by-step explanation:
area of a square = side²
2601m² = side²
√(2601m²) = √side²
51m = side
perimeter of a square = 4*side
perimeter of this square = 4*51
perimeter of this square = 204m
Answer:
I got 25.6cm² but I could be wrong