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mamaluj [8]
2 years ago
8

Enzel goes online to buy a graphing calculator. He finds a site that currently has a promotion of 15% off on all orders over $50

. Enzel decides to buy his graphing calculator, with a price tag of $83, at this site because he knows that he will get the 15% discount when he checks out. Enzel pays 4. 5% sales tax on the discounted price and pays a shipping fee of $6. 35. What is the total of Enzel’s online purchase? a. $80. 07 b. $80. 36 c. $86. 74 d. $93. 09 Please select the best answer from the choices provided A B C D.
Mathematics
1 answer:
Sonbull [250]2 years ago
8 0

Based on the cost of the calculator, the discount, the shipping fee, and the tax, the total cost of the purchase was<u> a. $80.07</u>

The cost of the calculator was:

<em>= Cost of calculator x ( 1  - discount)</em>

= 83 x ( 1 - 15%)

= $70.55

The sales tax would be:

= 70.55 x 4.5%

= $3.17

The total cost would be:

<em>= Cost + Sales tax + Shipping fee</em>

= 70.55 + 3.17 + 6.35

= $80.07

In conclusion, the total is $80.07.

<em>Find out more on such at brainly.com/question/11239587. </em>

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Answer:

x + y < 20

5x + 10y ≥ 100

Step-by-step explanation:

The ski club wants at least $100

Student pays $5

Chaperone pays $10

Maximum number of seats = 20

Assumption:

Assumed number of students = x

Assumed number of chaperone = y

Equation:

Maximum number of seats = 20

⇒ x + y < 20

The club wants $100

⇒ 5x + 10y ≥ 100

4 0
4 years ago
The diagonal of a square is 60 in, as shown
andre [41]

Answer:

The length of side is 42.4 inches.

Step-by-step explanation:

Given that:

Diagonal of square = 60 inches

As all sides of a square are equal, thus

Side of square = x

The diagonal will be the hypotenuse of a right angled triangle.

Using Pythagorean theorem;

x^2+x^2=(60)^2\\2x^2=3600\\x^2=\frac{3600}{2}\\x^2=1800

Taking square root on both sides

\sqrt{x^2}=\sqrt{1800}\\x=42.4

Hence,

The length of side is 42.4 inches.

5 0
3 years ago
Enter in the missing numbers to create equivalent ratios.
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Step-by-step explanation:

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Find the vectors T, N, and B at the given point. r(t) = &lt; t^2, 2/3t^3, t &gt;, (1, 2/3 ,1)
maxonik [38]

Answer with Step-by-step explanation:

We are given that

r(t)=< t^2,\frac{2}{3}t^3,t >

We have to find T,N and B at the given point t > (1,2/3,1)

r'(t)=

\mid r'(t) \mid=\sqrt{(2t)^2+(2t^2)^2+1}=\sqrt{(2t^2+1)^2}=2t^2+1

T(t)=\frac{r'(t)}{\mid r'(t)\mid}=\frac{}{2t^2+1}

Now, substitute t=1

T(1)=\frac{}{2+1}=\frac{1}{3}

T'(t)=\frac{-4t}{(2t^2+1)^2} +\frac{1}{2t^2+1}

T'(1)=-\frac{4}{9}+\frac{1}{3}

T'(1)=\frac{1}{9}=

\mid T'(1)\mid=\sqrt{(\frac{-2}{9})^2+(\frac{4}{9})^2+(\frac{-4}{9})^2}=\sqrt{\frac{36}{81}}=\frac{2}{3}

N(1)=\frac{T'(1)}{\mid T'(1)\mid}

N(1)=\frac{}{\frac{2}{3}}=

N(1)=

B(1)=T(1)\times N(1)

B(1)=\begin{vmatrix}i&j&k\\\frac{2}{3}&\frac{2}{3}&\frac{1}{3}\\\frac{-1}{3}&\frac{2}{3}&\frac{-2}{3}\end{vmatrix}

B(1)=i(\frac{-4}{9}-\frac{2}{9})-j(\frac{-4}{9}+\frac{1}{3})+k(\frac{4}{9}+\frac{2}{9})

B(1)=-\frac{2}{3}i+\frac{1}{3}j+\frac{2}{3}k

B(1)=\frac{1}{3}

5 0
3 years ago
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