Item 10 Find the median, first quartile, third quartile, and interquartile range of the data. 38,55,61,56,46,67,59,75,65,58
jok3333 [9.3K]
I think the median is 58.5, the first quartile is 50.5, the third quartile is 66, and finally, the interquartile range is <span>12.75.</span>
Answer: B. 2 = 3x + 10x2
Step-by-step explanation:
This is the concept of quadratic equations; We required to find the type of equation that can be solved using the model that has been used to solve the equation such that the answer is:
[-3+-sqrt(3^2+4(10)(2))]/(2(10))
The formual that was applied here was a quadratic formula given by:
x=[-b+\-sqrt(b^2-4ac)]/2a
whereby from the our substituted values above,
a=10,b=3 and c=-2
such that the quadratic equation will be:
10x^2+3x-2
He'll make 7 cuts. If you can't see that that is the answer, draw a diagram.
<span>7 * 5 = ?</span>
Answer:
B) Vertex (1,2), maximum
Step-by-step explanation:
First, determine if the graph has a maximum or a minimum value. Since the graph opens downwards, it has a <u>maximum</u> value.
The maximum is the point that has the greatest y value. We can see that the greatest y value is at 
. Going down two units from that spot, we can see that the x value is at 
. We can plug those into the vertex form, 
. By plugging in we get the point 
.
Answer:
A
Step-by-step explanation:
