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3 years ago

Find the value of x ........................

Mathematics

1 answer:

Free_Kalibri [48]3 years ago

8 0

Answer:

Step-by-step explanation: it is 2

And that is the Answer

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poizon [28]

I think the answer is D

8 0

4 years ago

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What is the value of x? <br> Please help me

marishachu [46]

Answer:

54=x

Step-by-step explanation:

2x+2=3x-52

this is because they are opposite alternating angles so now we can re arrange the equation.

54=x

4 0

2 years ago

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Ten hunters are waiting for ducks to fly by. When a flock of ducks flies overhead, the hunters fire at the same time, but each c

Lerok [7]

Answer:

The expected number of ducks that escape unhurt is:

Step-by-step explanation:

First the process is binomial process. Having said this, we have 10 hunters, and 10 ducks flying overhead while the hunter take their shot at the same time.

By expected value, we mean average or mean. And the mean of a binomial distribution is:

Mean => E(x) = np.

We must also know that there is only two probability possibilities:

1. The hunter hits the duck (p)

2. The hunter misses the duck (1-p) = q.

Hence;

p = 1/2, and (1-p) = 1/2.

Therefore;

E(x) = np; where n is the total number of hunter.

E(x) = 10*(1/2) = 5

The expected number of ducks that escape unhurt is 5

3 0

4 years ago

Do these have the same horizontal asymptote or no?

Svet_ta [14]

No it doesn’t have horizontal asymptote

3 0

3 years ago

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A TEACHER IS CONSTRUCTING A MATHEMATICS TEST

Nuetrik [128]

The number of ways of constructing questions from the pool of 28 questions if her test is to have 3 difficult, 4 average and 3 easy questions is 924, 000 ways

<h3>How to determine the combination</h3>

Note that the formula for combination is given as;

Combination = $\frac{n!}{r!(n-r)!}$

From the information we have that;

There are 28 questions in the pool

The test should have a total of 10 questions;

6 difficult , 10 average and 12 easy questions

We are asked to determine the combination of;

3 difficult questions

4 average questions

3 easy questions

6C3 = $\frac{6!}{3!(6-3)!}$

6C3 = $\frac{720}{36}$

6C3 = 20

10C4 = $\frac{10!}{4!(10-4)!}$

10C4 = $\frac{3628800}{17280}$

10C4 = 210

12C4 = $\frac{12!}{4!(12-4)!}$

12C4 = 220

The number of ways of constructing the questions is

= 20 × 210 × 220

= 924, 000 ways

Thus, the number of ways of constructing questions from the pool of 28 questions if her test is to have 3 difficult, 4 average and 3 easy questions is 924, 000 ways

Learn more about combination here:

brainly.com/question/4658834

#SPJ1

7 0

2 years ago