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azamat
2 years ago
7

Pleaseeeee help on this one

Mathematics
1 answer:
lutik1710 [3]2 years ago
6 0
First find volume of prism by doing l*w*h so 12*4*6=288
Then find volume of triangular prism by doing 1/2*b*h*l so 1/2*6*6*4=72
Lastly add these 2 together for the volume of the entire composite shape:
288+72
=360
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6th grade math i mark as brainliest
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What is 10*10? Please help! :) ​
Zigmanuir [339]

Answer:

100

Step-by-step explanation:

It will help in the future to memorize your time tables

10*10 is basically 10 plus 10, 10 times but in a easier form

10+10+10+10+10+10+10+10+10+10=100

10+10=20

20+10=30

30+10=40

40+10=50

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2 years ago
Rewrite the polynomial in standerd form f(x)=(3x+1)(x+2)(x-3)
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3 years ago
Given LaTeX: f\left(x\right)=x^{^3}-3x+4f ( x ) = x 3 − 3 x + 4, determine the intervals where the function is increasing and wh
Vedmedyk [2.9K]

Answer:

Increasing: x and x>1.

Decreasing: -1

Step-by-step explanation:

We have been given a function f(x)=x^3-3x+4. We are asked to determine the intervals, where the function is increasing and where it is decreasing.

First of all, we will find critical points of our given function by equating derivative of our given function to 0.

Let us find derivative of our given function.

f'(x)=\frac{d}{dx}(x^3)-\frac{d}{dx}(3x)+\frac{d}{dx}(4)

f'(x)=3x^{3-1}-3+0

f'(x)=3x^{2}-3

Let us equate derivative with 0 as find critical points as:

0=3x^{2}-3

3x^{2}=3

Divide both sides by 3:

x^{2}=1

Now we will take square-root of both sides as:

\sqrt{x^{2}}=\pm\sqrt{1}

x=\pm 1

x=-1,1

We know that these critical points will divide number line into three intervals. One from negative infinity to -1, 2nd -1 to 1 and 3rd 1 to positive infinity.

Now we will check one number from each interval. If derivative of the point is greater than 0, then function is increasing, if derivative of the point is less than 0, then function is decreasing.

We will check -2 from our 1st interval.

f'(-2)=3(-2)^{2}-3=3(4)-3=12-3=9

Since 9 is greater than 0, therefore, function is increasing on interval (-\infty, -1) \text{ or } x.

Now we will check 0 for 2nd interval.

f'(0)=3(0)^{2}-3=0-3=-3

Since -3 is less than 0, therefore, function is decreasing on interval (-1,1) \text{ or } -1.

We will check 2 from our 3rd interval.

f'(2)=3(2)^{2}-3=3(4)-3=12-3=9

Since 9 is greater than 0, therefore, function is increasing on interval (1,\infty) \text{ or } x>1.

6 0
3 years ago
Which results only in a horizontal compression of y = 1/x by a factor of x?
KIM [24]

Your answer is A. y = 1/6x

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3 years ago
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