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3 years ago

What is the area of the trapezoid?

Mathematics

1 answer:

Akimi4 [234]3 years ago

4 0

Answer:

264 cm^2.

Step-by-step explanation:

The area = 1/2 * height * sum of the parallel sides

= 1/2 * 12 * (28 + 16)

= 6 * 44

= 264 cm^2.

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Nine students in Maddie's classroom are wearing red. There are

goblinko [34]

Answer:

She is correct because 30 percent of 30 is 9 or in other words if you multiply 30 by 30 percent you get 9.

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

a triangle has an area of 54 m2 and a height of 9m how long is the base of the triangle entered your answer in the box

Delvig [45]

Answer:
base of the triangle = 12 m

Explanation:
Area of the triangle = 1/2 * base * height
We are given that:
area = 54 m^2
height = 9 m

Substitute in the equation to get the base as follows:
Area of the triangle = 1/2 * base * height
54 = 1/2 * base * 9
108 = 9*base
base = 12 m

Hope this helps :)

7 0

3 years ago

Read 2 more answers

3 moon + 1 star = 29 1 moon +1 moon = 15 Find value of 1 moon

Montano1993 [528]

Hi!

I can help you with joy!

3 moons+1 star equals 29.

All right.

Actually, there are a few numbers that can be hidden behind the moon:

3*8=24 + 1 star (5) = 29

But 1 moon + 1 moon equals 15.

So one moon equals 7.5.

$*GentleGirlie*$

8 0

3 years ago

three bags of sweets weigh 27/4 kg. two of them have the same weight and the third bag is heavier than each of the bags of equal

Nana76 [90]

I'm here buddy,

so, let's take the value of the two bags with equal weight as x.

= x + x + (x + $\frac{6}{5}$ ) = $\frac{27}{4}$

= 3x + $\frac{6}{5}$ = $\frac{27}{4}$

= 3x = $\frac{27}{4}$ - $\frac{6}{5}$

( let's take the LCM of 4 and 5 = 20

= 3x = $\frac{135}{20}$ - $\frac{24}{20}$

= 3x = $\frac{111}{20}$

= x = $\frac{111}{20}$ ÷ $\frac{3}{1}$ = $\frac{111}{20}$ × $\frac{1}{3}$ = $\frac{37}{20}$

So, the weight of the equal bags are $\frac{37}{20}$ and the weight of the third bag ( heavy one ) is $\frac{37}{20}$ + $\frac{6}{5}$ = $\frac{37}{20}$ + $\frac{24}{20}$ = $\frac{61}{20}$

1st bag = $\frac{37}{20}$ kg

2nd bag = $\frac{37}{20}$ kg

3rd bag = $\frac{61}{20}$ kg

Hope it helps...

7 0

3 years ago

If g(x) = 3x - 4, what is the value of g-(g(-2))? 100 X + 4 3 10

kozerog [31]

-g(-2) is 10

Step-by-step explanation:

Step 1:

Given g(x) = 3x - 4. Find g(-2).

⇒ g(-2) = 3 × -2 - 4 = -6 - 4 = -10

Step 2:

Find -g(-2)

⇒ -g(-2) = -(-10) = 10

3 0

3 years ago