All categories

3 years ago

Noelle has set a goal to run more than 50 mi this month. So far, she has run 10 mi. Her average running speed is 5 mph.

Mathematics

1 answer:

Vladimir79 [104]3 years ago

3 0

Answer:

To meet her goal, Noelle must run more than $8\ hours$ the rest of the month

Step-by-step explanation:

Let

h-------> the number of hours Noelle runs for the rest of the month

we know that

The inequality that represent the situation is

$10+5h>50$

Solve for h

Subtract 10 both sides

$5h> 50-10$

$5h> 40$

Divide by 5 both sides

$h> 8\ hours$

You might be interested in

What is the solution to the equation above

KonstantinChe [14]

Answer:

A = 3/4

Step-by-step explanation:

alternately could equal 0.75

5 0

2 years ago

Evaluate each expression for g=10 9-4g+1=?

Viktor [21]

-30, 10*4=40 so you do 9-40+1 which is equal to -30

5 0

3 years ago

Read 2 more answers

Question 22 Petrolyn motor oil is a combination of natural oil and synthetic oil. It contains 8 liters of natural oil for every

Setler [38]

Answer:

897 liters

Step-by-step explanation:

The motor oil is composed of 8 liters of natural oil and 5 liters of synthetic oil. This means there is a ratio of 8/5. We have 552 liters of natural oil to y liters of synthetic. This is the ratio 552/y. Create a proportion that compares the two ratios.

$\frac{8}{5}=\frac{552}{y}$

Solve by cross multiplying.

8y = 5(552)

8y = 2,760

y= 345

345 liters of synthetic oil.

Together 552+345= 897 liters of motor oil.

4 0

3 years ago

The area of the shaded region is 20 cm. Find the value of x

dolphi86 [110]

If you could put more info ab this then i would understand what u want me to put

3 0

2 years ago

What is the length side of a triangle that has vertices at (-5, -1), (-5, 5), and (3, -1)?

Rasek [7]

The side lengths of triangle are 6 units, 8 units and 10 units.

<u>SOLUTION: </u>

Given that, we have to find what is the length side of a triangle that has vertices at (-5, -1), (-5, 5), and (3, -1)

We know that, distance between two points $P\left(x_{1}, y_{1}\right) \text { and } Q\left(x_{2}, y_{2}\right)$ is given by

$P Q=\sqrt{\left(x_{2}-x_{1}\right)^{2}+\left(y_{2}-y_{1}\right)^{2}}$

Now,

$\begin{array}{l}{\text { Distance between }(-5,-1) \text { and }(-5,5)=\sqrt{(-5-(-5))^{2}+(5-(-1))^{2}}} \\\\ {\qquad \begin{array}{l}{=\sqrt{(-5-(-5))^{2}+(5-(-1))^{2}}} \\\\ {=\sqrt{(0)^{2}+(5+1)^{2}}=\sqrt{(6)^{2}}=6} \\\\ {=\sqrt{(-5)^{2}+(5+1)^{2}+(5-(-1))^{2}}} \\\\ {=\sqrt{(-8)^{2}+(5+1)^{2}}=\sqrt{64+36}=\sqrt{100}=10} \\\\ {=\sqrt{(3-1)^{2}+(-1-(-1))^{2}}} \\\\ {=\sqrt{(5+3)^{2}+(0)^{2}}=\sqrt{(8)^{2}}=8}\end{array}}\end{array}$

8 0

3 years ago