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Leona [35]
3 years ago
7

What is the approximate area of a circle enclosed by a piece of rope 50.24 inches long? (Use the fact that π ≈ 3.14 to make your

calculations.)
Mathematics
1 answer:
Nikitich [7]3 years ago
3 0

Answer:

the approximate area of this circle is 200.96 inches long.

Step-by-step explanation:

To answer this problem we need to remember that the area of a circle is given by the formula:

Area = πr^2 where r is the radius.

and the perimeter is:

Perimeter = 2πr

Now, the problem tells us that the circle is enclosed by a piece of rope that's 50.24 inches long. So the perimeter of the circle is 50.24 inches.

Since we have the value of the perimeter and the value of pi, we are going to substitute these values in the perimeter formula to find r.

Perimeter = 2πr

50.24=2(3.14)r

50.24= 6.28r

50.24/6.28= r

8= r

Thus, the radius of the circle is 8 inches long.

Now, we can use this value to find the area of the circle:

Area = πr^2

Area = π8^2

Area = 3.14 (64)

Area = 200.96

Therefore, the approximate area of this circle is 200.96 inches long.

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stellarik [79]

Answer:

<em>The Graph is shown below</em>

Step-by-step explanation:

<u>The Graph of a Function</u>

Given the function:

\displaystyle y=g(x)=-\frac{3}{2}(x-2)^2

It's required to plot the graph of g(x). Let's give x some values:

x={-2,0,2,4,6}

And calculate the values of y:

\displaystyle y=g(-2)=-\frac{3}{2}(-2-2)^2=-\frac{3}{2}(-4)^2==-\frac{3}{2}*16=-24

Point (-2,-24)

\displaystyle y=g(0)=-\frac{3}{2}(0-2)^2=-\frac{3}{2}(-2)^2=-\frac{3}{2}*4=-6

Point (0,-6)

\displaystyle y=g(2)=-\frac{3}{2}(2-2)^2=-\frac{3}{2}(0)^2=0

Point (2,0)

\displaystyle y=g(4)=-\frac{3}{2}(4-2)^2=-\frac{3}{2}(2)^2=-\frac{3}{2}*4=-6

Point (4,-6)

\displaystyle y=g(6)=-\frac{3}{2}(6-2)^2=-\frac{3}{2}(4)^2=-\frac{3}{2}*16=-24

Point (6,-24)

The graph is shown in the image below

8 0
2 years ago
Each of the 25 balls in a certain box is either red, blue or white and has a number from 1 to 10 painted on it. If one ball is t
Aneli [31]

Answer:

Not sufficient information

Step-by-step explanation:

Probability of white ball: P(W)

Probability of even number: P(E)

Probability of white ball or even number: P(W∨E) is asked

Considering case (1):

Probability of white ball and even number: P(W∧E) = 0

And we know that,

P(W∨E) = P(W) + P(E) - P(W∧E) = P(W) + P(E) - 0 = P(W) + P(E)

It is not sufficient to calculate the desired probability.

Considering case (2):

P(W) - P(E) = 0.2

Here, it is possible for P(W) and P(E) to get multiply values.

So P(W∨E) cannot be determined.

Considering cases (1) & (2):

P(W∧E) = 0 and P(W) - P(E) = 0.2

So, P(W∨E) = P(W) + P(E) = P(E) + 0.2 + P(E) = 2P(E) + 0.2

Again multiple answers are possible.

Such as, for P(E) = 0.4 (10 even balls) ⇒ P(W∨E) = 1

but for P(E) = 0.2 (5 even balls) ⇒ P(W∨E) = 0.6

So, the information are not sufficient.

3 0
3 years ago
Tamica is making a fruit salad. She spends $3.30 on 6 kiwis, $8.40 on 3 pounds of grapes and $8.54 for 7 bananas.
Ludmilka [50]

Answer: how come you don't know the answer what grade are you in

6 0
3 years ago
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Find the sum and classify the polynomial based on degree and number of terms.
Elis [28]
3rd option or letter c
8 0
3 years ago
Solve the equation for 0° ≤ x ≤ 90°. Round to the nearest degree. tan^2 B = 4
Anettt [7]

<u>ANSWER</u>

B=63\degree


<u>EXPLANATION</u>

We want to solve the trigonometric equation;


tan^2(B)=4, where 0\degree \le B \le 90\degree.


Taking square root of both sides gives,


tan(B)=\pm \sqrt{4}


tan(B)=\pm 2


Since B is in the first quadrant, we proceed with;


tan(B)=2, because the tangent ratio is positive in the first quadrant.


\Rightarrow B =arctan(2)


\Rightarrow B =63.43\degree.


Correct to the nearest degree,


B =63\degree




7 0
3 years ago
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