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mina [271]
3 years ago
5

Please help, i have to finish this right now

Mathematics
2 answers:
nirvana33 [79]3 years ago
5 0
1 is not linear 2. Is linear 3. Is not linear
Naddik [55]3 years ago
3 0
1st one: linear
2nd one: linear
3rd one: nonlinear
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Subtract I need help^_^
trapecia [35]
The answer to this subtraction is d
6 0
3 years ago
Which trigonometric identity can be used to prove the given statement?<br> tan0 cos0 = sin0
Ilia_Sergeevich [38]

Answer:

Step-by-step explanation:

Free trigonometric identity calculator - verify trigonometric identities step-by-step This website uses cookies to ensure you get the best experience. By using this website, you agree to our Cookie Policy.

4 0
2 years ago
How do you this question (pre-cal)
Novay_Z [31]

The goal to proving identities is to transform one side into the other. We can only pick one side to transform while the other side stays the same the entire time. The general rule of thumb is to transform the more complicated side (though there may be exceptions to this guideline).

So I'll take the left hand side and try to turn it into \csc^2( B )

One way we can do that is through the following steps:

\frac{\tan(B) + \cot(B)}{\tan(B)} = \csc^2(B)\\\\\frac{\tan(B)}{\tan(B)} + \frac{\cot(B)}{\tan(B)} = \csc^2(B)\\\\1 + \cot(B)*\frac{1}{\tan(B)} = \csc^2(B)\\\\1 + \cot(B)*\cot(B) = \csc^2(B)\\\\1 + \cot^2(B) = \csc^2(B)\\\\1 + \frac{cos^2(B)}{\sin^2(B)} = \csc^2(B)\\\\\frac{sin^2(B)}{\sin^2(B)}+\frac{cos^2(B)}{\sin^2(B)} = \csc^2(B)\\\\\frac{sin^2(B)+cos^2(B)}{\sin^2(B)} = \csc^2(B)\\\\\frac{1}{\sin^2(B)} = \csc^2(B)\\\\\csc^2(B)=\csc^2(B) \ \ {\Large \checkmark}\\\\

Since we've shown that the left hand side transforms into the right hand side, this verifies the equation is an identity.

4 0
3 years ago
A repeated-measures study comparing two treatments with n = 4 participants produces md = 2 and ss = 75 for the difference scores
valentinak56 [21]

The estimated standard error for the sample mean difference is  2.5 .

According to the question

A repeated-measures study comparing two treatments

n = 4

MD(mean difference) = 2

SS (sum of square) = 75

Now,

error for the sample  

Formula for standard error

S^{2} = \frac{SS}{n-1}

by substituting the value

S^{2} = \frac{75}{4-1}

S^{2} = \frac{75}{3}

S² = 25

S = 5 (s is never negative)

Standard error of the estimate for the sample mean difference

As

The standard error of the estimate is the estimation of the accuracy of any predictions.

The formula for standard error of the mean difference

standard error of the mean difference  =\frac{standard\\\ error}{\sqrt{n} }  

standard error of the mean difference = \frac{5}{\sqrt{4} }  

standard error of the mean difference = 2.5

Hence, the estimated standard error for the sample mean difference is  2.5 .

To know more about estimated standard error here:

brainly.com/question/14524236

#SPJ4

5 0
1 year ago
How do i do #3? I dont know how to do the whole problem.
lisov135 [29]
You have to put the problem down we cant help you if its not there
sorry but please put equation in or problem
3 0
3 years ago
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