The system of equations has infinitely many solutions
<em><u>Solution:</u></em>
<em><u>Given system of equations are:</u></em>
-3x + 3y = 12 ------- eqn 1
y = x + 4 --------- eqn 2
We have to find the solution to the system of equations
We can use substitution method
Substitute eqn 2 in eqn 1
-3x + 3(x + 4) = 12
-3x + 3x + 12 = 12
-3x + 12 = -3x + 12
If we have terms with same terms on both sides of equal sign, then we have infinitely many solutions
Thus the system of equations has infinitely many solutions
Answer:
Step-by-step explanation:
First confirm that x = 1 is one of the zeros.
f(1) = 2(1)^3 - 14(1)^2 + 38(1) - 26
f(1) = 2 - 14 + 38 - 26
f(1) = -12 + 38 = + 26
f(1) = 26 - 26
f(1) = 0
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next perform a long division
x -1 || 2x^3 - 14x^2 + 38x - 26 || 2x^2 - 12x + 26
2x^3 - 2x^2
===========
-12x^2 + 28x
-12x^2 +12x
==========
26x -26
26x - 26
========
0
Now you can factor 2x^2 - 12x + 26
2(x^2 - 6x + 13)
The discriminate of the quadratic is negative. (36 - 4*1*13) = - 16
So you are going to get a complex result.
x = -(-6) +/- sqrt(-16)
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2
x = 3 +/- 2i
f(x) = 2*(x - 1)*(x - 3 + 2i)*(x - 3 - 2i)
The zeros are
1
3 +/- 2i
<h2>
Answer:</h2>
please see analysis
<h2>
Step-by-step explanation:</h2>
F
<em>I hope this helps you:)</em>
