What is the slope of 2x-3

9 divided by 4 in drawing form

jolli1 [7]

Answer: that’s 2.25

Step-by-step explanation:

ok so you draw 4 big circles then and 1 in each one then just keep going 2 so that 2

5 0

3 years ago

Write each phrase as an algebraic expression

Tpy6a [65]

tye findamental theorem of calculs is cognitive

4 0

3 years ago

The radius of a circle is 13 find its area un terms of pi

Leto [7]

The area of the circle is given as:

$A=\pi r^2$

Plugging the value of the radius we have that:

$A=\pi(13)^2=169\pi$

Therefore the area in terms of pi is:

$A=169\pi$

7 0

1 year ago

What function is shown by the graph below?

Airida [17]

Answer:

The function $f(x)=\sqrt{x+2}$ is shown by the graph below ⇒ 2nd answer

Step-by-step explanation:

<em>To find the right function chose two points from the graph and substitute the x-coordinate of each point in the function to find the y-coordinate, if they are the same with the corresponding y-coordinates of the points, then the function is shown by the graph</em>

From the figure:

The curve passes through points (-2 , 0) and (2 , 2)

∵ $f(x)=\sqrt{x-2}$

∵ x = -2

- Substitute x by -2

∴ $f(-2)=\sqrt{-2-2}$

∴ $f(-2)=\sqrt{-4}$ ⇒ it is impossible no square root for (-) number

∴ $f(x)=\sqrt{x-2}$ is not the function shown by the graph

∵ $f(x)=\sqrt{x+2}$

∵ x = -2

- Substitute x by -2

∴ $f(-2)=\sqrt{-2+2}$

∴ $f(-2)=\sqrt{0}$

∴ f(-2) = 0 ⇒ same as the y-coordinate of x = -2

∵ x = 2

- Substitute x by 2

∴ $f(2)=\sqrt{2+2}$

∴ $f(2)=\sqrt{4}$

∴ f(2) = 2 ⇒ same as the y-coordinate of x = 2

∴ The function $f(x)=\sqrt{x+2}$ is shown by the graph below

7 0

3 years ago

5) In a certain supermarket, a sample of 60 customers who used a self-service checkout lane averaged 5.2 minutes of checkout tim

Ne4ueva [31]

Answer:

$\S^2_p =\frac{(60-1)(3.1)^2 +(72 -1)(2.8)^2}{60 +72 -2}=8.643$

$S_p=2.940$

$t=\frac{(5.2 -6.1)-(0)}{2.940\sqrt{\frac{1}{60}+\frac{1}{72}}}=-1.751$

$df=60+72-2=130$

$p_v =P(t_{130}$

Assuming a significance level of $\alpha=0.05$ we have that the p value is lower than this significance level so then we can conclude that the mean for checkout time is significantly less for people who use the self-service lane

Step-by-step explanation:

Data given

Our notation on this case :

$n_1 =60$ represent the sample size for people who used a self service

$n_2 =72$ represent the sample size for people who used a cashier

$\bar X_1 =5.2$ represent the sample mean for people who used a self service

$\bar X_2 =6.1$ represent the sample mean people who used a cashier

$s_1=3.1$ represent the sample standard deviation for people who used a self service

$s_2=2.8$ represent the sample standard deviation for people who used a cashier

Assumptions

When we have two independent samples from two normal distributions with equal variances we are assuming that

$\sigma^2_1 =\sigma^2_2 =\sigma^2$

The statistic is given by:

$t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{S_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2}}}$

And t follows a t distribution with $n_1+n_2 -2$ degrees of freedom and the pooled variance $S^2_p$ is given by this formula:

$\S^2_p =\frac{(n_1-1)S^2_1 +(n_2 -1)S^2_2}{n_1 +n_2 -2}$

System of hypothesis

Null hypothesis: $\mu_1 \geq \mu_2$

Alternative hypothesis: $\mu_1 < \mu_2$

This system is equivalent to:

Null hypothesis: $\mu_1 - \mu_2 \geq 0$

Alternative hypothesis: $\mu_1 -\mu_2 < 0$

We can find the pooled variance:

$\S^2_p =\frac{(60-1)(3.1)^2 +(72 -1)(2.8)^2}{60 +72 -2}=8.643$

And the deviation would be just the square root of the variance:

$S_p=2.940$

The statistic is given by:

$t=\frac{(5.2 -6.1)-(0)}{2.940\sqrt{\frac{1}{60}+\frac{1}{72}}}=-1.751$

The degrees of freedom are given by:

$df=60+72-2=130$

And now we can calculate the p value with:

$p_v =P(t_{130}$

Assuming a significance level of $\alpha=0.05$ we have that the p value is lower than this significance level so then we can conclude that the mean for checkout time is significantly less for people who use the self-service lane

5 0

3 years ago