Answer:
A. Do your own research including reading articles related to the same topic.
Explanation:
To confirm online information that is not made by reputable experts, professionals, journals, or websites, it is always recommended to cross-check such information carefully. To do that is to make research on the same topic and confirm if the actual information is the same.
Hence, in this case, the correct answer is "Do your own research including reading articles related to the same topic."
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The correct answer that would best complete the given statement above would be the word VIRUSES. Here is the complete statement. Viruses can only grow and multiply within the cells of another living thing, but they can remain active on a surface for several hours or days.
Answer:
denial-of-service attack (DoS attack) and distributed denial-of-service attack (DDoS attack)
Explanation:
Denial-of-service attack -
It is a type of cyber attack , where the hacker can create a machine or any network resource , which is capable to disrupt the server of the host , with the help of the internet , is referred to as the denial of service attack .
The task is accomplished with by flooding the host with many superfluous requests , which can overload the system .
In case of the distributed denial-of-service attack , the flooding is done by many different sources .
Hence , from the given scenario of the question ,
The correct answer is denial-of-service attack (DoS attack) and distributed denial-of-service attack (DDoS attack) .
Answer:
// code in C++
#include <bits/stdc++.h>
using namespace std;
// main function
int main()
{
// variables
int sum_even=0,sum_odd=0,eve_count=0,odd_count=0;
int largest=INT_MIN;
int smallest=INT_MAX;
int n;
cout<<"Enter 10 Integers:";
// read 10 Integers
for(int a=0;a<10;a++)
{
cin>>n;
// find largest
if(n>largest)
largest=n;
// find smallest
if(n<smallest)
smallest=n;
// if input is even
if(n%2==0)
{
// sum of even
sum_even+=n;
// even count
eve_count++;
}
else
{
// sum of odd
sum_odd+=n;
// odd count
odd_count++;
}
}
// print sum of even
cout<<"Sum of all even numbers is: "<<sum_even<<endl;
// print sum of odd
cout<<"Sum of all odd numbers is: "<<sum_odd<<endl;
// print largest
cout<<"largest Integer is: "<<largest<<endl;
// print smallest
cout<<"smallest Integer is: "<<smallest<<endl;
// print even count
cout<<"count of even number is: "<<eve_count<<endl;
// print odd cout
cout<<"count of odd number is: "<<odd_count<<endl;
return 0;
}
Explanation:
Read an integer from user.If the input is greater that largest then update the largest.If the input is smaller than smallest then update the smallest.Then check if input is even then add it to sum_even and increment the eve_count.If the input is odd then add it to sum_odd and increment the odd_count.Repeat this for 10 inputs. Then print sum of all even inputs, sum of all odd inputs, largest among all, smallest among all, count of even inputs and count of odd inputs.
Output:
Enter 10 Integers:1 3 4 2 10 11 12 44 5 20
Sum of all even numbers is: 92
Sum of all odd numbers is: 20
largest Integer is: 44
smallest Integer is: 1
count of even number is: 6
count of odd number is: 4
