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Misha Larkins [42]

2 years ago

6

Explain the effect that "h" has on the function f(x) = a(x - h)2 + k.

1 answer:

saw5 [17]2 years ago

6 0

The expression given by f(x)=a(x-h)^2+k is a the equation of a vertex where (h,k) is the vertex. The importance of h is that it represents the x-intercept, the lowest or the highest point of the graph of the expression. This is a very important factor when determining the turning points of parabolas

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saveliy_v [14]

$- \frac{6}{5} x - 4 = - 46 \\ - \frac{6}{5} x = - 42 \\ - 6x = - 210 \\ x = 35$
Translate the words into math and solve for x. Any questions let me know.

3 0

3 years ago

If log2 5 = k, determine an expression for log32 5 in terms of k.

lukranit [14]

Answer:

$log_3_2(5)=\frac{1}{5} k$

Step-by-step explanation:

Let's start by using change of base property:

$log_b(x)=\frac{log_a(x)}{log_a(b)}$

So, for $log_2(5)$

$log_2(5)=k=\frac{log(5)}{log(2)}\hspace{10}(1)$

Now, using change of base for $log_3_2(5)$

$log_3_2(5)=\frac{log(5)}{log(32)}$

You can express $32$ as:

$2^5$

Using reduction of power property:

$log_z(x^y)=ylog_z(x)$

$log(32)=log(2^5)=5log(2)$

Therefore:

$log_3_2(5)=\frac{log(5)}{5*log(2)}=\frac{1}{5} \frac{log(5)}{log(2)}\hspace{10}(2)$

As you can see the only difference between (1) and (2) is the coefficient $\frac{1}{5}$ :

So:

$\frac{log(5)}{log(2)} =k\\$

$log_3_2(5)=\frac{1}{5} \frac{log(5)}{log(2)} =\frac{1}{5} k$

6 0

2 years ago

CAN SOMEONE PLEASE HELP ME. I NEED HELP ON THIS QUESTION

sleet_krkn [62]

Answer:

a segment cd only

Step-by-step explanation:

segment cd is the only line that passes through segment ab at a right angle

4 0

3 years ago

It’s just 2.a answer please

Inessa05 [86]

You have to convert the 30 inches into you know what and add them all together

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3 years ago

What is 5/8.65 I want my work to see work

Bond [772]

I hope this helps you

6 0

3 years ago