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melisa1 [442]
3 years ago
6

What steps are needed for word to create an index

Computers and Technology
2 answers:
Taya2010 [7]3 years ago
7 0

Answer:

<u>Position the insertion pointer where you want the index to appear</u>.

(the insertion point is the point where the next characters typed from the keyboard will appear)

If you want the index to start on a new page, create a new page in the program you're using

<u>Then you click the References tab.</u>

<u>In the Index group, click the Insert Index button. </u>

When the Index dialog box appears, <u>click the OK button to insert the index into your document.</u>

8_murik_8 [283]3 years ago
4 0

Answer:

Do this:

Position the insertion pointer where you want the index to appear. If you want the index to start on a new page, create a new page in Word. ...

Click the References tab.

In the Index group, click the Insert Index button. The Index dialog box appears. ...

Click the OK button to insert the index into your document.

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What mode is generally used when delivering a presentation to an audience?
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Two functions of the UPS​
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2. Consider a 2 GHz processor where two important programs, A and B, take one second each to execute. Each program has a CPI of
allsm [11]

Answer:

program A runs in 1 sec in the original processor and 0.88 sec in the new processor.

So, the new processor out-perform the original processor on program A.

Program B runs in 1 sec in the original processor and 1.12 sec in the new processor.

So, the original processor is better then the new processor for program B.

Explanation:

Finding number of instructions in A and B using time taken by the original processor :

The clock speed of the original processor is 2 GHz.

which means each clock takes, 1/clockspeed

= 1 / 2GH = 0.5ns

Now, the CPI for this processor is 1.5 for both programs A and B. therefore each instruction takes 1.5 clock cycles.

Let's say there are n instructions in each program.

therefore time taken to execute n instructions

= n * CPI * cycletime = n * 1.5 * 0.5ns

from the question, each program takes 1 sec to execute in the original processor.

therefore

n * 1.5 * 0.5ns = 1sec

n = 1.3333 * 10^9

So, number of instructions in each program is 1.3333 * 10^9

the new processor :

The cycle time for the new processor is 0.6 ns.

Time taken by program A = time taken to execute n instructions

=  n * CPI * cycletime

= 1.3333 * 10^9 * 1.1 * 0.6ns

= 0.88 sec

Time taken by program B = time taken to execute n instructions

= n * CPI * cycletime

= 1.3333 * 10^9 * 1.4 * 0.6

= 1.12 sec

Now, program A runs in 1 sec in the original processor and 0.88 sec in the new processor.

So, the new processor out-perform the original processor on program A.

Program B runs in 1 sec in the original processor and 1.12 sec in the new processor.

So, the original processor is better then the new processor for program B.

5 0
2 years ago
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