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photoshop1234 [79]
3 years ago
15

X and y are positive integers. explain why incorrect to claim that

Mathematics
1 answer:
dedylja [7]3 years ago
4 0

You can find counterexamples to disprove this claim. We have positive integers that are perfect square numbers; when we take the square root of those numbers, we get an integer.

For example, the square root of 1 is 1, which is an integer. So if y = 1, then the denominator becomes an integer and thus we get a quotient of two integers (since x is also defined to be an integer), the definition of a rational number.

Example: x = 2, y = 1 ends up with \frac{2}{\sqrt{1}} = \frac{2}{1} which is rational. This goes against the claim that x/\sqrt{y} is always irrational for positive integers x and y.

Any integer y that is a perfect square will work to disprove this claim, e.g. y = 1, y = 4, y= 9, y = 16. So it is not always irrational.

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The answer to #2?? I already have the graph but I still need the answer
Sidana [21]
If we have 

y = 6x + 1 and x - y = 11, we can take advantage of  y - y = 0 as follows:
                                         Subtract x from both sides of the 2nd equation:
                                         -y = 11 - x

Now combine 

 y = 6x + 1
-y = 11 - x
--------------
0 = 5x + 12.  Solving for x, x = -12/5.     Using the equation above, find y:
                                                               -y = 11 - x
                                                                   = 11 - (-12/5)
                                                                   = 55/5 + 12/5 = 67/5

Then the solution is (-12.5, 67/5).

                      
3 0
4 years ago
Malik collects rare stamps and has a total of 212 stamps. He has 34 more domestic stamps than foreign stamps. Let x represent th
Effectus [21]

Answer:

y = 89 x = 123

Step-by-step explanation:

since they're both in standard form, its easier to do the process of elimination

x - y = 34

-x -y -212

------------------

-2y = -178

y = 89

now plug in y to any one of those two equations

x - y = 34

x - 89 = 34

x = 123

<em>to check:</em>

<em>x</em><em> </em><em>+</em><em> </em><em>y</em><em> </em><em>=</em><em> </em><em>2</em><em>1</em><em>2</em>

<em>1</em><em>2</em><em>3</em><em> </em><em>+</em><em> </em><em>8</em><em>9</em><em> </em><em>=</em><em> </em><em>2</em><em>1</em><em>2</em>

<em>2</em><em>1</em><em>2</em><em> </em><em>=</em><em> </em><em>2</em><em>1</em><em>2</em>

6 0
3 years ago
Work out 12+8÷(9-5) 0.018÷0.06 Express as single fraction 5/7÷2/5
Anettt [7]

Step-by-step explanation:

I don't know if the first set of numbers is all in one set, but I'll do my best to give you an answer.

Really all you need to do is use PEMDAS for the first question.

(Parentheses, exponents, multiply, divide, add, subtract. In that order)

1 2 + 8 \div (9 - 5) \\ 12 + 8 \div 4 \\ 12 + 2 \\ 14

Then to simplify that fraction next to it, notice that 0.018 is 3x 0.06.

that's a 3:1 ratio, so it ends up simplifying to this:

\frac{3}{1}

Lastly, to solve the division of that fraction. If you divide by a fraction, you multiply whatever it's dividing by its inverse.

So...

\frac{5}{7}  \div  \frac{2}{5}  \\  \frac{5}{7}  \times  \frac{5}{2}  \\  \frac{25}{14}

7 0
3 years ago
6) What happens to the diameter of the field of view as the magnification increases?
Diano4ka-milaya [45]

Answer:

There is an inverse relationship between the total magnification and the diameter of the field of view – i.e., as magnifications increases the diameter of the field decreases in proportion, so the diameter of field of view at different magnification can be calculated mathematically, using the formula.

Step-by-step explanation:

4 0
4 years ago
Find the equation of the line passing<br> through the points (3,3) and (4,5).<br> y = [? ]x +[ ?]
muminat

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3 0
3 years ago
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