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3 years ago

Is (-2,-6) a solution of y < 7x + 8?

Mathematics

2 answers:

mojhsa [17]3 years ago

6 0

Answer:

not a solution

Step-by-step explanation:

y < 7x + 8

Substitute (2-,-6) into the inequality

-6 < 7(-2) +8

-6 <-14+8

-6 <-6

This is not true because they are equal not less than

sveticcg [70]3 years ago

6 0

Answer: false

Step-by-step explanation:

-6<7(-2)+8

-6<-6

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Paha777 [63]

Step-by-step explanation:

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3 years ago

The answer to the picture please

Vinil7 [7]

the required ans is 3√b+b/3b

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3 years ago

Find the area of the triangle defined by the coordinates (-3, -4), (-7, 0), and (-3, 4).

mr Goodwill [35]

The area of a Triangle is 1/2BH (B=Base length, H=Height)
When looking at the points, we can figure out the following:

The distance between the two points at the base is 8 (to get from -4 to 4 you must add 8) and the height is 4 (to get from -4 to 0 as well as 0 to 4, the distance is 4).

Now we plug in our values:
Area= 1/2(8)(4)
=1/2(32)
=16 Units squared

Therefore, your answer is 16 units squared.

I hope this Helps!
-Sinnamin

3 0

2 years ago

Consider the two data sets below:

alina1380 [7]

Answer:

Option c) The data sets will have the same values of their interquartile range.

Explanation:

1. The values are in order: they are in increasing oder, from lowest to highest value.

2. Calculate the interquartile range.

Interquartile range, IQR, is the third quartile, Q3, less the first quartile Q1:

IQR = Q3 - Q1

To find the first and the third quartile, first find the median:

Data Set 1: 19, 25, 35, 38, 41, 49, 50, 52, 59

[19, 25, 35, 38], 41, [49, 50, 52, 59]

↑

median = 41

Data Set 2: 19, 25, 35, 38, 41, 49, 50, 52, 99

[19, 25, 35, 38] , 41, [49, 50, 52, 99]

↑

median = 41

Now find the median of each subset: the values below the median and the values above the median.

Data set 1: First quartile

[19, 25, 35, 38],

↑

Q1 = [25 + 35] / 2 = 30

Third quartile

[49, 50, 52, 59]

↑

Q3 = [50 + 52] / 2 = 51

IQR = Q3 - Q1 = 51 - 30 = 21

Data set 2: First quartile

[19, 25, 35, 38]

↑

Q1 = [25 + 35] / 2= 30

Third quartile

[49, 50, 52, 99]

↑

Q3 = [52 + 50]/2 = 51

IQR = 51 - 30 = 21

Thus, it is shown that the data sets have will have the same values for the interquartile range: IQR = 21. (option c)

This happens because replacing one extreme value (in this case the maximum value) by other extreme value does not affect the median.

An outlier will change the range because the range is the maximum value less the minimum value.

5 0

2 years ago

PLEASEEE I NEED HELPPP!!!!

taurus [48]

Answer:

#carry on learning

mark me as brainliest

Find a point-slope form for the line that satisfies the stated conditions. Slope , passing through (-5,4)

I really need this question answered

By:

I don't see a value for the slope. We need that to set the equation, otherwise I can write an unlimited number of equations that pass through (-5,4).

I'll assume a slope so that you can see how the procedure would work. I like 6, so we'll assume a slope of 6.

The equation for a straight line has the form y = mx + b, where m is the slope and y is the y-intercept, the value of y when x = 0. We want a line that has slope 6, so:

y = 6x + b

We need to find b, so substitute the point (-5,4) that we know is on the line:

4 = 6*(-5) + b and solve for b

4 = -30 + b

b = 34

The line is y = 6x + 34

4 0

2 years ago

Is (-2,-6) a solution of y < 7x + 8?​

Is (-2,-6) a solution of y < 7x + 8?