Is (-2,-6) a solution of y < 7x + 8?

Mathematics

2 answers:

mojhsa [17]3 years ago

6 0

Answer:

not a solution

Step-by-step explanation:

y < 7x + 8

Substitute (2-,-6) into the inequality

-6 < 7(-2) +8

-6 <-14+8

-6 <-6

This is not true because they are equal not less than

sveticcg [70]3 years ago

6 0

Answer: false

Step-by-step explanation:

-6<7(-2)+8

-6<-6

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Ray Of Light [21]

Answer:

not sure

Step-by-step explanation:

7 0

2 years ago

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gladu [14]

Answer:

Step-by-step explanation:

First I converted the fractions into decimals to make it easier to solve.

2 1/2 —> 2.5

1 3/4 —> 1.75

Then I added the two decimals together.

2.5 + 1.75 = 4.25

Then I divided this number by 100 (the number of cups in one bag)

100/4.25=23.529

With this equation I know that one bag lasts 23 full days.

This is almost a month, and so it would not make sense for the answers to be B, C, or D.

Hope this helped

8 0

2 years ago

Read 2 more answers

Someone can help??

oee [108]

Answer:

Step-by-step explanation:

let cos^{-1}x=t

cos t=x

when x=1,cos t=1=cos 0

t \rightarrow 0

$\lim_{x \to 1} \frac{1-\sqrt{x}}{(cos ^{-1}x)^2 } \\= \lim_{t \to 0} \frac{1-\sqrt{cos~t}}{t^2} \times \frac{1+\sqrt{cos~t}}{1+\sqrt{cos ~t}} \\= \lim_{t \to 0} \frac{1-cos~t}{t^2(1+\sqrt{cos~t})}} \\= \lim_{t \to 0 }\frac{2 sin^2~\frac{t}{2}}{t^2(1+\sqrt{cos~t})}} \\= 2\lim_{t \to 0 }(\frac{sin~t/2}{\frac{t}{2} })^2 \times \frac{1}{4} \times \lim_{t \to 0 }\frac{1}{1+\sqrt{cos~t}} \\=\frac{2}4} \times 1^2 \times \frac{1}{1+\sqrt{cos~0}} \\=\frac{1}{2} \times \frac{1}{1+1} \\=\frac{1}{4}$