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Fed [463]
3 years ago
10

On the average, 1 1/3 bushels of seed are needed to plant 1 acre of wheat. How many bushels of seed would be required to plant 3

0 acres?
Mathematics
1 answer:
Bess [88]3 years ago
6 0

Answer:40 bushels of seed would be required to plant 30 acres of wheat.

Step-by-step explanation:

On the average, 1 1/3 bushels of seed are needed to plant 1 acre of wheat. Converting 1 1/3 bushels of seed to improper fraction, it becomes 4/3 bushels of seed.

Let x represent the bushels of seed that would be required to plant 30 acres. Therefore

4/3 bushels of seed = 1 acre

x = 30 acres

Cross multiplying

x × 1 = 4/3 × 30

x = 40 bushels of seed

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X+4/4=x/x-2<br> A:{-4,2} <br> B:{-2,4}<br> C:{}
Andreyy89

Answer:

<u>The correct answer is B. {-2,4}</u>

Step-by-step explanation:

Let's solve for x, this way:

x + 4/4 = x /x -2

(x + 4) * ((x - 2) = 4 * x

x² - 2x + 4x -8 = 4x

x² - 2x + 4x -8 - 4x = 0

x² - 2x  -8 = 0

(x - 4) * (x +2) = 0

x - 4 = 0

x + 2 = 0

x₁ = 4

x₂ = - 2

<u>The correct answer is B. {-2,4}</u>

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How do I solve 8/x-0.16=0.64
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7. the last one

I = P R T

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