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Fed [463]
3 years ago
10

On the average, 1 1/3 bushels of seed are needed to plant 1 acre of wheat. How many bushels of seed would be required to plant 3

0 acres?
Mathematics
1 answer:
Bess [88]3 years ago
6 0

Answer:40 bushels of seed would be required to plant 30 acres of wheat.

Step-by-step explanation:

On the average, 1 1/3 bushels of seed are needed to plant 1 acre of wheat. Converting 1 1/3 bushels of seed to improper fraction, it becomes 4/3 bushels of seed.

Let x represent the bushels of seed that would be required to plant 30 acres. Therefore

4/3 bushels of seed = 1 acre

x = 30 acres

Cross multiplying

x × 1 = 4/3 × 30

x = 40 bushels of seed

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work for a publishing company. The company wants to send two employees to a statistics conference. To be​ fair, the company deci
Yuki888 [10]

Answer:

(a) S = {MR, MJ, MD, MC, RJ, RD, RC, JD, JC, DC}

(b) The probability that Roberto and John attend the​ conference is 0.10.

(c) The probability that Clarice attends the​ conference is 0.40.

(d) The probability that John stays​ home is 0.60.

Step-by-step explanation:

It is provided that :

Marco (<em>M</em>), Roberto (<em>R</em>), John (<em>J</em>), Dominique (<em>D</em>) and Clarice (<em>C</em>) works for the company.

The company selects two employees randomly to attend a statistics conference.

(a)

There are 5 employees from which the company has to select two employees to send to the conference.

So the total number of ways to select two employees is:

{5\choose 2}=\frac{5!}{2!(5-2)!}=\frac{5\times 4\times 3!}{2\times 3!}=10

The 10 possible samples are:

MR, MJ, MD, MC, RJ, RD, RC, JD, JC, DC

(b)

The probability of the event <em>E</em> is:

P(E)=\frac{n(E)}{N}

Here,

n (E) = favorable outcomes

N = Total number of outcomes.

The variable representing the selection of  Roberto and John is, <em>RJ</em>.

The favorable number of outcomes to select Roberto and John is, 1.

The total number of outcomes to select 2 employees is 10.

Compute the probability that Roberto and John attend the​ conference as follows:

P(RJ)=\frac{n(RJ)}{N}=\frac{1}{10}=0.10

Thus, the probability that Roberto and John attend the​ conference is 0.10.

(c)

The favorable outcomes of the event where Clarice attends the conference are:

n (C) = {MC, RC, JC and DC} = 4

Compute the probability that Clarice attends the​ conference as follows:

P(C)=\frac{n(C)}{N}=\frac{4}{10}=0.40

Thus, the probability that Clarice attends the​ conference is 0.40.

(d)

The favorable outcomes of the event where John does not attends the conference are:

n (J') = MR, MD, MC, RD, RC, DC

Compute the probability that John stays​ home as follows:

P(J')=\frac{n(J')}{N}=\frac{6}{10}=0.60

Thus, the probability that John stays​ home is 0.60.

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3 years ago
Find the area for the following figure.<br> O 124. 86 cm2<br> 62.93 cm2<br> 26.5 cm2<br> 137.45 cm2
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You have to figure out how many 32 ounces are in 96. the answer to that is 3. you then multiply 2 pints times 3 to get 6.

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