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masha68 [24]
3 years ago
7

Which point (x,y) is a solution to the system of linear equations?

Mathematics
1 answer:
alukav5142 [94]3 years ago
5 0
You need to post the two equations that make up the “system”
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(Anderson, 1.14) Assume that P(A) = 0.4 and P(B) = 0.7. Making no further assumptions on A and B, show that P(A ∩ B) satisfies 0
Goshia [24]

Answer with Step-by-step explanation:

We are given that

P(A)=0.4 and P(B)=0.7

We know that

P(A)+P(B)+P(A\cap B)=P(A\cup B)

We know that

Maximum value of P(A\cup B)=1 and minimum value of P(A\cup B)=0

0\leq P(A\cup B )\leq 1

0\leq P(A)+P(B)-P(A\cap B)\leq 1

0\leq 0.4+0.7-P(A\cap B)\leq 1

0\leq 1.1-P(A\cap B)\leq 1

0\leq 1.1-P(A\cap B)

P(A\cap B)\leq 1.1

It is not possible that P(A\cap B) is equal to 1.1

1.1-P(A\cap B)\leq 1

-P(A\cap B)\leq 1-1.1=-0.1

Multiply by (-1) on both sides

P(A\cap B)\geq 0.1

Again, P(A\cup B)\geq P(B)

0.4+0.7-P(A\cap B)\geq 0.7

1.1-P(A\cap B)\geq 0.7

-P(A\cap B)\geq -1.1+0.7=-0.4

Multiply by (-1) on both sides

P(A\cap B)\leq 0.4

Hence, 0.1\leq P(A\cap B)\leq 0.4

3 0
3 years ago
Two thirds of a number is no more than -10
Aliun [14]
Let x be the number in the problem. When it states that x is "no more than -10", it means than it is less than or equal to -10. So, we have

\frac{2}{3}x≤-10

In order to cancel out the \frac{2}{3} on the left and isolate x, we multiply both sides by \frac{3}{2} (since \frac{3}{2}·\frac{2}{3}=1). Thus, we have

x≤-10·\frac{3}{2}=-15

Therefore, x≤-15

7 0
3 years ago
Someone answer this random question
gayaneshka [121]

Answer:

hmmmmm... thats a tough one

its probably ur mom

Step-by-step explanation:

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4 years ago
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Gennadij [26K]

Answer:

sorryyyy i dont know the answer :-(

Step-by-step explanation:

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Write an equation in slope-intercept form for the line with slope -1/4
jarptica [38.1K]

Answer:

The equation would be Y=-1/4X+5

And in the above pic , i have graph the line , too .

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