Question

Solve with quadratic formula 8x^2-9x-5=0

Answer 1

$8x^{2} - 9x - 5 = 0$

$x = \frac{-(-9) +/- \sqrt{(-9)^{2} - 4(8)(-5)}}{2(8)}$

$x = \frac{9 +/- \sqrt{81 + 160}}{16}$

$x = \frac{9 +/- \sqrt{241}}{16}$

$x = \frac{9 +/- 15.524}{16}$

<u />$x = 0.5625 +/- 0.97025$
$x = 0.5625 + 0.97025$                                   $x = 0.5625 - 0.97025$
$x = 1.53275$                                                  $x = -0.40775$