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4 years ago

15% of the apples in a crate are rotten. There are 12 rotten apples in the crate.

Mathematics

2 answers:

Llana [10]4 years ago

6 0

12 apples = 15% of the total apples.

Find 1% by dividing 12 by 15:

12/15=0.8

Find 100% of the number of apples by multiplying 0.8 by 100:

0.8*100=80

There are 80 apples in the crate.

ladessa [460]4 years ago

4 0

12/80
=15 percent

There are 80 apples in the crate

Do 12 divided by 15 then multiply by 100 = 80

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marysya [2.9K]

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3 years ago

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2 years ago

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3 years ago

A photograph 8 cm by 11 cm will be framed. The combined area of the frame and photograph will be 180 cm^2. Algebraically determi

SCORPION-xisa [38]

Answer:

12 cm x 15 cm

Step-by-step explanation:

if the picture frame thickness is x,

then the frame dimension would be (8+2x) cm by (11+2x) cm

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3 years ago

What is the first derivative of r with respect to t (i.e., differentiate r with respect to t)? r = 5/(t2)Note: Use ^ to show exp

adelina 88 [10]

Answer:

The first derivative of $r(t) = 5\cdot t^{-2}$ (r(t)=5*t^{-2}) with respect to t is $r'(t) = -10\cdot t^{-3}$ (r'(t) = -10*t^{-3}).

Step-by-step explanation:

Let be $r(t) = \frac{5}{t^{2}}$ , which can be rewritten as $r(t) = 5\cdot t^{-2}$ . The rule of differentiation for a potential function multiplied by a constant is:

$\frac{d}{dt}(c \cdot t^{n}) = n\cdot c \cdot t^{n-1}$ , $\forall \,n\neq 0$

Then,

$r'(t) = (-2)\cdot 5\cdot t^{-3}$

$r'(t) = -10\cdot t^{-3}$ (r'(t) = -10*t^{-3})

The first derivative of $r(t) = 5\cdot t^{-2}$ (r(t)=5*t^{-2}) with respect to t is $r'(t) = -10\cdot t^{-3}$ (r'(t) = -10*t^{-3}).

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3 years ago