The equation that represents the line shown in the graph is:
B. y = -3x + 2
<h3>Further explanation</h3>
Solving linear equation mean calculating the unknown variable from the equation.
Let the linear equation : y = mx + c
If we draw the above equation on Cartesian Coordinates , it will be a straight line with :
<em>m → gradient of the line</em>
<em>( 0 , c ) → y - intercept</em>
<em>Gradient of the line could also be calculated from two arbitrary points on line</em><em> ( x₁ , y₁ )</em><em> and </em><em>( x₂ , y₂ ) </em><em>with the formula :</em>

<em>If point </em><em>( x₁ , y₁ )</em><em> is on the line with gradient </em><em>m</em><em> , the equation of the line will be :</em>

Let us tackle the problem!
From the graph , the line goes through the point ( -1 , 5 ) and ( 0 , 2 ).
Let:
<em>( x₁ , y₁ ) = ( 0 , 2 )</em>
<em>( x₂ . y₂ ) = ( -1 , 5 )</em>

We can calculate the gradient of the graph by using this following formula:





Next , we can find the equation of the graph by using this following formula:





<h3>Learn more</h3>
<h3>Answer details</h3>
Grade: High School
Subject: Mathematics
Chapter: Linear Equations
Keywords: Linear , Equations , 1 , Variable , Line , Gradient , Point