41º
1) Since we want to find the reference angle for a -139º angle, we need to resort to the following formula
2) Note that a -139 angle is in quadrant III, since negative angles are clockwise oriented
3) Thus the Reference Angle is 41º
1) find the mean,
20+10+30+20+50+30+40+20/8= 27.5
2) Find the distance of each value from that mean
20- 7.5
10- 17.5
30- 2.5
20-7.5
50- 22.5
30- 2.5
40- 12.5
20- 7.5
3) Find the mean of those distances
7.5+17.5+2.5+7.5+22.5+2.5+12.5+7.5/8=10
The Mean absolute deviation for this data set is 10.
Answer:
1385
Step-by-step explanation:
1) the difference is d=25-8=42-25=17;
the sequence given in the condition is arithmetic one (linear relationship).
2) in order to calculate the value of the 82d term:
a(n)=a(1)+d*(n-1), where n - number of required term (it is 82), then
a(82)=8+17*(82-1)=8+1377=1385.
When you have an equation with two variables, it's easier to graph it in the form y=mx+b. b is the y-intercept - the x-value at which y is equal to zero, and m is the slope of the graph.
So if I have the equation 3x+2y=12, I have to first subtract 3x from both sides.
2y=-3x+12. Now I have to divide the whole thing by 2 to get my y value alone. y=-3/2x+6.
Now, to graph it, I have to first plot the point where y equals zero and x equals six. Then you plug in different numbers above and below this. When x=5, you get y=-3/2*5 + 6 which is -1.5. So you have the point (5, -1.5) and also the point (6, 0). You can plug in 0 for y and solve for x to find the x-intercept, or when x=0. 0=-3/2x+6. Subtract six from both sides. -6=-3/2x. Divide both sides by -3/2. 4=x. So you have another point - (4,0).
Now that you have three points, you can connect them with a line and add arrows to the end.
Hope I helped!
Answer:
B. I and III
Step-by-step explanation:
I and III both have the same data:
March, 73
April 74
May 78
June 84
July 75
II has different data
March 71
April 72
May 85
June 90
July 60
Since I and III have the exact same data, choice B is the best answer
Hope this helps! :)
