Answer:
Possible locker numbers for Selma are: 3, 5 and 29
Step-by-step explanation:
First of all, let us have a look at the definition of a prime number.
A <em>prime number</em> is a number which is divisible either by 1 or the number itself.
No other number divides the prime number other than 1 and the number itself.
Now, let us factorize the given number 435 and let us observe the what all possibilities are there.
Factorizing 145 further:
No further factors are possible.
Therefore 3, 5 and 29 are the prime factors of 435.
So, the answer is:
Possible locker numbers for Selma are: 3, 5 and 29
From the problem, the vertex = (0, 0) and the focus = (0, 3)
From the attached graphic, the equation can be expressed as:
(x -h)^2 = 4p (y -k)
where (h, k) are the (x, y) values of the vertex (0, 0)
The "p" value is the difference between the "y" value of the focus and the "y" value of the vertex.
p = 3 -0
p = 3
So, we form the equation
(x -0)^2 = 4 * 3 (y -0)
x^2 = 12y
To put this in proper quadratic equation form, we divide both sides by 12
y = x^2 / 12
Source:
http://www.1728.org/quadr4.htm
Answer:
Step-by-step explanation:
Isolate the variable, a. Note the equal sign, what you do to one side, you do to the other. Do the opposite of PEMDAS.
PEMDAS is the order of operation and stands for:
Parenthesis
Exponents (& Roots)
Multiplication
Division
Addition
Subtraction
First, add 3 to both sides of the equation:
u = -3a - 3
u (+3) = -3a - 3 (+3)
u + 3 = -3a
Next, divide -3 from both sides of the equation:
(u + 3)/-3 = (-3a)/-3
a = (u + 3)/-3
is your answer.
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You can write the question as a inequality.
c - 2 ≥ -22
add 2 on both sides...
c ≥ -20
Your answer is c ≥ -20.
Answer:
x=7 DO=25 OG=35
Step-by-step explanation:
4x-3+2x+21=60 4(7)-3 2(7)+21
4x+2x -3+21 28-3=25 14+21=35
6x+18=60 DO=25 OG=35
60-18=42
6x=42
42/6=7
x=7
