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Alekssandra [29.7K]
4 years ago
11

Three multiples of 2/3

Mathematics
1 answer:
Genrish500 [490]4 years ago
6 0

Answer:

Multiples of 2/3 are  4/3, 2, and 8/3

Step-by-step explanation:

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Step-by-step explanation:

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3 years ago
In 5 years, Dad will be three times as old as his daughter Jill will be then. If the sum of their present ages is 50, how old ar
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The answer is <span>b.3x + 15 = 55 - x
</span>
x - Jill's present age
y - dad's present age

<span>In 5 years, Dad will be three times as old as his daughter Jill will be then:
y + 5 = 3(x + 5)

</span><span>The sum of their present ages is 50:
x + y = 50

We have the system of two equations now:
</span>y + 5 = 3(x + 5)
x + y = 50

Let's rearrange the second equation:
If:         x + y = 50     
Then:  y = 50 - x

Now, substitute y from the second equation (y = 50 - x) into the first one:
y + 5 = 3(x + 5)
50 - x + 5 = 3(x + 5)
50 + 5 - x = 3*x + 3*5
55 - x = 3x + 15

Rearrange it a bit:
3x + 15 = 55 - x
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5 0
3 years ago
Show that in any group of 101 people there are at least two persons having the same number friends (It is assumed that if a pers
vladimir1956 [14]

Answer:

Step-by-step explanation:

Let us assume that if possible in the group of 101, each had a different number of friends.  Then the no of friends 101 persons have 0,1,2,....100 only since number of friends are integers and non negative.

Say P has 100 friends then P has all other persons as friends.  In this case, there cannot be any one who has 0 friend.  So a contradiction.  Hence proved

Part ii: EVen if instead of 101, say n people are there same proof follows as

if different number of friends then they would be 0,1,2...n-1

If one person has n-1 friends then there cannot be any one who does not have any friend.

Thus same proof follows.

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Answer data gathering

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