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zheka24 [161]
4 years ago
10

Who is greater 2/3 or 7/8

Mathematics
2 answers:
horrorfan [7]4 years ago
8 0
2/3 = 16/24

7/8 = 21/24

21/24 >16/24
7/8is larger
eduard4 years ago
4 0
2/3= 16/24


7/8= 21/24

So, 7/8 is larger.
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After spending 30% of her salary Sara was able to deposit $120 in the bank. What is her salary?
Katena32 [7]

Answer: $400

Step-by-step explanation:

So first you set it up in a equation. You put the amount she put in the bank over x (the x represents her full salary) which equals the percent she already spent over her full salary. That would be 120/x=30/100 you would then cross-multiply to get 12,000 = 30x. you then divide 30 from both sides to get x =400.

3 0
3 years ago
Find the missing value.<br> 2 cookies<br> $3.00<br> 4 cookies<br> X
sergiy2304 [10]
6 dollars because if 2 is equal to 300 dollars just double it to get 6 dollars
3 0
3 years ago
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What is the area of the region bounded between the curves y=x and y=sqrt(x)?
erastova [34]

Answer:

\frac{1}{6}

Step-by-step explanation:

y = x     .....(1)

y=\sqrt{x}     .... (2)

By solving equation (1) and equation (2)

x = \sqrt{x}

\sqrt{x}\left ( \sqrt{x}-1 \right )=0

\sqrt{x}=0 or \left ( \sqrt{x}-1 \right )=0

x = 0, x = 1

y = 0, y = 1

A = \int_{0}^{1}ydx(curve)-\int_{0}^{1}ydx(line)

A = \int_{0}^{1}\sqrt{x}dx-\int_{0}^{1}xdx

A = \frac{2}{3}[x^\frac{3}{2}]_{0}^{1}-\frac{1}{2}[x^2]_{0}^{1}

A = \frac{2}{3}-\frac{1}{2}

A = \frac{1}{6}

8 0
3 years ago
Can someone please help solve 2-7!!! I will give brainliest!!!
patriot [66]
Question 2 is 19.4 I hope I helped!
8 0
3 years ago
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Use the Distributive Property to solve the equation. 3x-5(x-4)=-9+5x+15
Norma-Jean [14]

Answer:

I keep getting no solution

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

5(x−4)=−9+5x+15

(5)(x)+(5)(−4)=−9+5x+15(Distribute)

5x+−20=−9+5x+15

5x−20=(5x)+(−9+15)(Combine Like Terms)

5x−20=5x+6

5x−20=5x+6

Step 2: Subtract 5x from both sides.

5x−20−5x=5x+6−5x

−20=6

Step 3: Add 20 to both sides.

−20+20=6+20

0=26

7 0
3 years ago
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