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AnnyKZ [126]
3 years ago
11

I am thinking of a number. If you triple my number and subtract 11, you get my number plus 33. What's my number?"

Mathematics
1 answer:
Aneli [31]3 years ago
8 0

Answer:

22

Step-by-step explanation:

22 x 3 = 66

66- 11 = 55

55-33 = 22

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The following are the ratings of males by females in an experiment involving speed dating. Use the given data to construct a box
Finger [1]

Answer:

Step-by-step explanation:

Box plot is enclosed.

To find out 5 number summary

3.0, 3.5, 4.5, 5.5, 6.5, 6.5, 7.0, 7.0, 7.0, 7.0, 7.0, 7.5, 8.0, 9.0, 9.0, 9.0, 9.5, 9.5, 9.5, 9.5}

Minimum: 3.0

Quartile Q1: 6.5

Median: 7

Quartile Q3: 9

Maximum: 9.5

Besides we find that

Average (mean): μ=7.25

Absolute deviation: 30.5

Mean deviation: 1.525

Minimum: 3.0

Maximum: 9.5

Variance: 3.7125

Standard deviation σ=1.926

4 0
3 years ago
Can someone please teach me how to add, subtract, multiply and divide negative numbers?
dedylja [7]
If both numbers are negative u add those up and ur answer will be a negative. so number one is negative 9.
if there is more positive ur answer will be a positive. so number 2 is 13.
number is more complicated so negative 3 +4 is 1 because u have more positive and u just subtract those then 1 minus 8 equals negative 7 and negative 7 minus 7 is 0. hope this helps
3 0
3 years ago
Read 2 more answers
Help me
lakkis [162]

Answer:

1/6x.(-18) is the answer

6 0
3 years ago
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Referring to the figure, find the sine of<br> ∠A. Give answer in simplest form.
STatiana [176]

Answer

150

Step-by-step explanation:

4 0
3 years ago
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Help! If you know this can you tell me how to do it?
aleksandr82 [10.1K]

Answer:

c

Step-by-step explanation:

Here's how this works:

Get everything together into one fraction by finding the LCD and doing the math.  The LCD is sin(x) cos(x).  Multiplying that in to each term looks like this:

[sin(x)cos(x)]\frac{sin(x)}{cos(x)}+[sin(x)cos(x)]\frac{cos(x)}{sin(x)} =?

In the first term, the cos(x)'s cancel out, and in the second term the sin(x)'s cancel out, leaving:

\frac{sin^2(x)}{sin(x)cos(x)}+\frac{cos^2(x)}{sin(x)cos(x)}=?

Put everything over the common denominator now:

\frac{sin^2(x)+cos^2(x)}{sin(x)cos(x)}=?

Since sin^2(x)+cos^2(x)=1, we will make that substitution:

\frac{1}{sin(x)cos(x)}

We could separate that fraction into 2:

\frac{1}{sin(x)}×\frac{1}{cos(x)}

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Therefore, the simplification is

sec(x)csc(x)

5 0
4 years ago
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