The zeros of the function f(x) = -(x + 1)(x - 3)(x + 2) are -1, 3, and -2, and the y-intercept of the function is located at (0,6)
<h3>The complete question</h3>
The zeros of the function f(x) = -(x + 1)(x - 3)(x + 2) are –1, 3, and __and the y-intercept of the function is located at (0,__)
<h3>How to determine the zeros?</h3>
The function is given as:
f(x) = -(x + 1)(x - 3)(x + 2)
Set the function to 0
-(x + 1)(x - 3)(x + 2) = 0
Divide both sides by - 1
(x + 1)(x - 3)(x + 2) = 0
Split
x + 1 = 0, x - 3 = 0 and x + 2 = 0
Solve for x
x = -1, x = 3 and x = -2
Hence, the zeros of the function f(x) = -(x + 1)(x - 3)(x + 2) are -1, 3, and -2
<h3>How to determine the y-intercept?</h3>
The function is given as:
f(x) = -(x + 1)(x - 3)(x + 2)
Set x to 0
f(0) = -(0 + 1)(0 - 3)(0 + 2)
Evaluate
f(0) = 6
Hence, the y-intercept of the function is located at (0,6)
Read more about functions at:
brainly.com/question/20691826
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