All categories

3 years ago

The difference of a number p and 6

Mathematics

1 answer:

frez [133]3 years ago

7 0

P-6 because you subtract the variable from the 6

You might be interested in

I'm not sure how to solve please help

wel

Follow these step:
So you want to start with adding the 5 to the other side of the equation so it would become 8=g/4
Then you want to multiply each side by 4 so it becomes 32=g

The answer is g=34
I hope this helps :)

8 0

3 years ago

If the markup rate is 50%, then the cost of a shirt that regularly sells for $60 is $40. true or false?

Natasha2012 [34]

Answer:

false

Step-by-step explanation:

half of 60 dollars is 30

think of it as half of 6

5 0

2 years ago

Please helppppppppppppppppppp

Stolb23 [73]

Answer:

50 feet

Step-by-step explanation:

Perimeter is the sum of all of the lengths of the sides.

A triangle has three sides, and three lengths are given, therefore all the sides are given.

The sum of the sides is 20 + 20 + 10 = 50

So the Perimeter is 50 feet

3 0

2 years ago

Read 2 more answers

Use the common ratio to find the next term of the geometric sequence. Type a numerical answer in the space provided.

prisoha [69]

Answer:

Step-by-step explanation:

the common ratio is 1/2 so you do 30(1/2)

30(1/2)=15

5 0

3 years ago

The recursive function LaTeX: f\left(0\right)=1,\:f\left(n\right)=f\left(n-1\right)+2nf ( 0 ) = 1 , f ( n ) = f ( n − 1 ) + 2 n

m_a_m_a [10]

Question:

The recursive function $f(0) = 1$ , $f(n) = f(n-1) + 2n$ represents the nth term of a sequence. Determine the explicit function

Answer:

$f(n) = n^2 + n+1$

Step-by-step explanation:

Given

$f(0) = 1$

$f(n) = f(n-1) + 2n$

Required

Write an explicit formula

Let n = 1

$f(1) = f(1-1) + 2*1$

$f(1) = f(0) + 2$

$f(1) = 1 + 2 = 3$

Let n = 2

$f(2) = f(2-1) + 2*2$

$f(2) = f(1) + 4$

$f(2) = 3 + 4 = 7$

Let n =3

$f(3)=f(3-1) + 2 * 3$

$f(3)=f(2) + 6$

$f(3)=7+ 6 = 13$

Let n = 4

$f(4) = f(4 - 1) + 2 * 4$

$f(4) = f(3) + 8$

$f(4) = 13+ 8 = 21$

So, we have:

$f(1) = 3= 1 + 2 * 1=1+0*1*2*1$

$f(2) = 7= 3 + 2 * 2=1+1*2+2*2$

$f(3) = 13= 7 + 2 * 3= 1+2*3+2*3$

$f(4) = 21 = 13 + 2 * 4= 1+3*4 +2 *4$

Following the above pattern:

$f(n) = 1 + (n - 1) * n + 2 * n$

$f(n) = 1 + n(n - 1) + 2n$

Open bracket

$f(n) = 1 + n^2 - n + 2n$

$f(n) = 1 + n^2 + n$

$f(n) = n^2 + n+1$

3 0

2 years ago