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UkoKoshka [18]
3 years ago
15

The difference of a number p and 6

Mathematics
1 answer:
frez [133]3 years ago
7 0
P-6 because you subtract the variable from the 6 
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Solve. k + 6 > 19
Readme [11.4K]

Answer:

k > 13

Step-by-step explanation:

k+6 > 19\quad :\quad \begin{bmatrix}\mathrm{Solution:}\:&\:k > 13\:\\ \:\mathrm{Interval\:Notation:}&\:\left(13,\:\infty \:\right)\end{bmatrix}

\mathrm{Subtract\:}6\mathrm{\:from\:both\:sides}

k+6-6 > 19-6

\mathrm{Simplify}

k > 13

Thus, the answer is k > 13

[RevyBreeze]

8 0
2 years ago
Write the equation in slope-intercept form of the line that passes through the points (-3, -10) and (5, 14)
hjlf

Answer:

-10, -3, 5, 14

Am not sure if this is correct

4 0
3 years ago
Read 2 more answers
On a trip to a lake, Kerrie and Shelly rode their bicycles four more than three times as many miles in the afternoon as in the m
Natalija [7]

Answer:

27 miles in the morning and 85 miles in the afternoon.

Explanation:

Let m be the number of miles they rode in the morning.  They rode 4 more than 3 times this many in the afternoon; this gives us the expression

3m+4

to represent the miles ridden in the afternoon.

Together they rode 112 miles; this means we add the morning miles, m, to the afternoon miles, 3m+4, and get 112:

m+3m+4 = 112

Combine like terms:

4m+4 = 112

Subtract 4 from each side:

4m+4-4= 112-4

4m = 108

Divide both sides by 4:

4m/4 = 108/4

m = 27

They rode 27 miles in the morning.

That means in the afternoon, they rode

3m+4 = 3(27)+4 = 81+4 = 85 miles.

5 0
3 years ago
Read 2 more answers
63% of what number is 252
storchak [24]

Answer:

We have, 63% × x = 252

or,

63/100 × x = 252

Multiplying both sides by 100 and dividing both sides by 63,

we have

x = 252 \times  \frac{100}{63 }

x = 400

<h3><u>PLEASE</u><u> MARK</u><u> ME</u><u> BRAINLIEST</u></h3>
7 0
3 years ago
The graphs below have the same shape. What is the equation of the red
anyanavicka [17]

Answer:

Option B is correct .

Step-by-step explanation:

According to Question , both the graph have same shape . If we look at the the first graph it cuts x - axis at (0 , 2) and ( 0 , -2) . Hence x = 2 and -2 are the zeroes of the equation .

And ,the given function is ,

\implies f(x) = 4 - x^2 \\\\\implies f(x) = 4-x^2=0 \\\\\implies 2^2-x^2=0\\\\\implies (2-x)(2+x) = 0 \\\\\boxed{\red{\bf \implies x = 2 , (-2) }}

<u>Hence ,we can can see that x = </u><u> </u><u>2</u><u> </u><u>and</u><u> </u><u>(</u><u>-</u><u>2</u><u>)</u><u> </u><u>are</u><u> </u><u>the</u><u> </u><u>zeroes </u><u>of </u><u>graph</u><u>. </u><u> </u>

This implies that if we know the zeroes , we can frame the Equation.

On looking at second parabola , it's clear that cuts x - axis at ( 1, 0 ) and (-1,0). So , 1 and -1 are the zeroes of the quadratic equation . Let the function be g(x) . Here , a and ß are the zeroes.

\implies g(x) = (x-\alpha)(x-\beta) \\\\\implies g(x) = (1+x)(1-x) \\\\\boxed{\pink{\bf \implies g(x) = 1 - x^2}}

<u>Hence </u><u>option </u><u>B</u><u> </u><u>is</u><u> </u><u>corre</u><u>ct</u><u> </u><u>.</u>

8 0
3 years ago
Read 2 more answers
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