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photoshop1234 [79]
2 years ago
9

Which is a tangent of circle P?pls helpt ASAP!!!!

Mathematics
1 answer:
oee [108]2 years ago
7 0
<h3>Answer: Choice C)  line n</h3>

Explanation:

Tangent lines touch the circle at exactly one point.

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Write the expression -3x 2 + 2y 2 + 5xy - 2y + 5x 2 - 3y 2 in simplest form. Then, answer the following questions using complete
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2x2 + 5xy - 3y
there are three terms in the simplified expression
there is one negative term in the simplified expression
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Bernita and Derek each plot a number on a number line. The numbers are unique but have the same absolute value. The sum of the a
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The correct answer is B. -75 and 75.

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75 + 75 = 150.
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Calculate the simple interest on each amount and the total amount at the end.
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Attached is a picture of my answers.

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2 years ago
A box contains 11 red chips and 4 blue chips. We perform the following two-step experiment: (1) First, a chip is selected at ran
Scilla [17]

Answer:

P(B1) = (11/15)

P(B2) = (4/15)

P(A) = (11/15)

P(B1|A) = (5/7)

P(B2|A) = (2/7)

Step-by-step explanation:

There are 11 red chips and 4 blue chips in a box. Two chips are selected one after the other at random and without replacement from the box.

B1 is the event that the chip removed from the box at the first step of the experiment is red.

B2 is the event that the chip removed from the box at the first step of the experiment is blue. A is the event that the chip selected from the box at the second step of the experiment is red.

Note that the probability of an event is the number of elements in that event divided by the Total number of elements in the sample space.

P(E) = n(E) ÷ n(S)

P(B1) = probability that the first chip selected is a red chip = (11/15)

P(B2) = probability that the first chip selected is a blue chip = (4/15)

P(A) = probability that the second chip selected is a red chip

P(A) = P(B1 n A) + P(B2 n A) (Since events B1 and B2 are mutually exclusive)

P(B1 n A) = (11/15) × (10/14) = (11/21)

P(B2 n A) = (4/15) × (11/14) = (22/105)

P(A) = (11/21) + (22/105) = (77/105) = (11/15)

P(B1|A) = probability that the first chip selected is a red chip given that the second chip selected is a red chip

The conditional probability, P(X|Y) is given mathematically as

P(X|Y) = P(X n Y) ÷ P(Y)

So, P(B1|A) = P(B1 n A) ÷ P(A)

P(B1 n A) = (11/15) × (10/14) = (11/21)

P(A) = (11/15)

P(B1|A) = (11/21) ÷ (11/15) = (15/21) = (5/7)

P(B2|A) = probability that the first chip selected is a blue chip given that the second chip selected is a red chip

P(B2|A) = P(B2 n A) ÷ P(A)

P(B2 n A) = (4/15) × (11/14) = (22/105)

P(A) = (11/15)

P(B2|A) = (22/105) ÷ (11/15) = (2/7)

Hope this Helps!!!

5 0
3 years ago
Help ༎ຶ‿༎ຶ i dont get it​
svetoff [14.1K]

Answer:

Step-by-step explanation:

You know the lengths of two sides and the angle between them, so use the Law of Cosines to find the third side.

x^2 = 10.5^2+ 5.4^2 -2(10.5)(5.4)cos20°

x ≈ 5.73 units

5 0
3 years ago
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