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3 years ago

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The jogging track at Francine’s school is 3/4 mile long. Yesterday Francine completed two laps on the track. If she ran 1/3 of t

he distance and walked the remainder of the way, how far did she walk?
(Give explanation as well please lol)

1 answer:

Alja [10]3 years ago

7 0

Answer:

1/2 of a mile

Step-by-step explanation:

Ok so she ran 1/3 of the distance and you know that the distance is 3/4 of a mile, so you multiply those two together and get 3/12 = 1/4. The total distance is 3/4 so 3/4 - 1/4 = 2/4 = 1/2

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A game involves rolling a fair six-sided die. If the number facing upward on the die is a whole number multiple of three, the pl

BaLLatris [955]

There is only two multiples of three on a six-sided die, the 3 side, and the 6 side.

3 x 20 = 60
6 x 20 = 120
120 + 60 = 180

$180.00 is your possible winnings total, but the question asks for your expected value on EACH roll, so you divide 180 by 6(sides on a die) to get your final answer

180/6 = 30

ANSWER: D. $30.00

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2 years ago

Read 2 more answers

What is the slope of the line represented by the equation y = –1/2x+1/4?

max2010maxim [7]

Answer:

A. -½

Step-by-step explanation:

In the Slope-Intercept Formula, <em>y = mx + b</em><em>,</em><em> </em><em>m</em><em> </em>represents the <em>rate</em><em> </em><em>of</em><em> </em><em>change</em><em> </em>[<em>slope</em>], so in this case, the slope is -½.

I am joyous to assist you anytime.

7 0

2 years ago

A bucket contains 40 red balls, 25 black balls, and 35 white balls. Two balls are drawn at random. What is the probability that

Lyrx [107]

Answer:

$Probability = \frac{1}{5}$ or $Probability = 0.2$

Step-by-step explanation:

Given

$Black = 25$

$White = 35$

$Red = 40$

Required

Determine the probability of selecting Black and Red

First, we need to calculate the number of red and black balls

The probability is calculated as thus:

$Probability = P(Black\ and \ Red) \ or\ P(Red\ and \ Black)$

Convert to mathematical expressions

$Probability = [P(Black) *P(Red)] + [P(Red) *P(Black)]$

Solve for each probaility;

$P(Black) = \frac{Black}{Total} = \frac{25}{100}$

$P(Red) = \frac{Red}{Total} = \frac{40}{100}$

So, we have:

$Probability = [P(Black) *P(Red)] + [P(Red) *P(Black)]$ $Probability = [\frac{25}{100} *\frac{40}{100}] + [\frac{40}{100} *\frac{25}{100}]$

$Probability = [\frac{1000}{10000}] + [\frac{1000}{10000}]$

$Probability = [\frac{1}{10}] + [\frac{1}{10}]$

$Probability = \frac{1+1}{10}$

$Probability = \frac{2}{10}$

$Probability = \frac{1}{5}$

or

$Probability = 0.2$

7 0

3 years ago

4 3/4 divided by 1 1/6

ozzi

Answer:

$2\frac{13}{22}$

Step-by-step explanation:

$=\frac{19}{4}\div \frac{11}{6}$

$\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{a}{b}\div \frac{c}{d}=\frac{a}{b}\times \frac{d}{c}$

$=\frac{19}{4}\times \frac{6}{11}$

$=\frac{19}{2}\times \frac{3}{11}$

$\mathrm{Multiply\:fractions}:\quad \frac{a}{b}\times \frac{c}{d}=\frac{a\:\times \:c}{b\:\times \:d}$

$=\frac{19\times \:3}{2\times \:11}$

$\mathrm{Multiply\:the\:numbers:}\:19\times \:3=57$

$=\frac{57}{2\times \:11}$

$\mathrm{Multiply\:the\:numbers:}\:2\times \:11=22$

$=\frac{57}{22}$

$=2\frac{13}{22}$

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2 years ago

The data shown in the table below can be

kvv77 [185]

Answer:

6: 12

7: 14

8: 16

Step-by-step explanation:

You do the last (y) term given [18] minus the first (y) term [10] given divided by how many terms it takes to get from the last (y) term given minus the first (y) term given [4]. So the equation looks like this:

(18 - 10)/4= 8/4 = 2

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3 years ago