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Art [367]
3 years ago
5

HELPPPPP

Mathematics
2 answers:
labwork [276]3 years ago
8 0

-8, -40, -50

edgenulty 2020

olchik [2.2K]3 years ago
3 0

Answer:

1st multiply g and f then h

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A line passes through the points (–5, 2) and (10, –1). Which is the equation of the line?
beks73 [17]

Slope = (2 + 1) / (-5 - 10) = -3/15 = - 1/5

Equation

y - 2 = -1/5 (x + 5)

y - 2 = -1/5 x - 1

y = -1/5 x + 1

Answer

y = -1/5 x + 1

6 0
3 years ago
Read 2 more answers
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Assoli18 [71]

Answer:

A. 560

Step-by-step explanation:

multiply 600 by 0.93 in order to find out what 93% of 600 is.

600 x 0.93 = 558

since 558 isn't one of the options you find which one is closest to it, then divide by 600 in order to see if it's still 93%

a) 560/ 600 = 0.93333 = 93.3%

there's your answer.

but to compare it with the rest of the answer choices:

b) 540 / 600 = 0.9 = 90%

c) 470 / 600 = 0.78333 = 78.3%

d) 490 / 600 = 0.81667 = 81.6%

none of these are in the range of 93, so they're incorrect

6 0
2 years ago
HURRY UP PLZZZZZ<br><br>I NEED TO FINISHHHH<br><br>I WILL MARK BRAINLYEST!!!<br>:)
andriy [413]

Answer:

I think 60

Step-by-step explanation:

have a great day

4 0
2 years ago
Read 2 more answers
PLEASE HELP Complete the table with<br> integer values of x from 0 to 4. Then graph the function.
irina1246 [14]

Answer:

y = 1 for the line.

Step-by-step explanation:

All values under y = 1. Surprisingly 1^0 is still 1. So just fill the table in with 1s under y.

I've drawn the line in desmos for you. I'm not sure whether you can extend the question enough to graph a line segment containing these 5 points (which is what I have done) or if you should just submit a graph with 4 points on. If it does not cost you anything to submit it twice, I would try the line first and the points alone the second time.

7 0
3 years ago
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liraira [26]

For x such that 0 < x < \frac{\pi}{2}, the mathematical expression is:

\frac{\sqrt{1 \;-cos^2x} }{sinx} + \frac{\sqrt{1 \;-sin^2x} }{cosx} = 1+1=2

<u>Given the following data:</u>

  • \frac{\sqrt{1 \;-cos^2x} }{sinx}

  • \frac{\sqrt{1 \;-sin^2x} }{cosx}

In Trigonometry, you should take note of the following mathematical expression:

sin^2x + cos^2x = 1

Therefore, we can obtain the following:

sin^2x  = 1 - cos^2x   ...equation 1.

cos^2x = 1 - sin^2x    ...equation 2.

Substituting the equations respectively, we have:

\frac{\sqrt{1 \;-cos^2x} }{sinx} + \frac{\sqrt{1 \;-sin^2x} }{cosx} = \frac{\sqrt{sin^2x} }{sinx} + \frac{\sqrt{cos^2x} }{cosx}\\\\

Taking the square roots, we have:

\frac{sinx}{sinx} + \frac{cosx}{cosx} = 1 +1\\\\1+1=2

Therefore, for x such that 0 < x < \frac{\pi}{2}, the expression is:

\frac{\sqrt{1 \;-cos^2x} }{sinx} + \frac{\sqrt{1 \;-sin^2x} }{cosx} = 1+1=2

Read more on trigonometry here: brainly.com/question/4515552

7 0
2 years ago
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