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UkoKoshka [18]
3 years ago
11

Can someone please help me?

Mathematics
1 answer:
Phoenix [80]3 years ago
4 0

Which one do you need assistance with?

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anzhelika [568]

3!=6

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What factor of the number 144is neither prime nor composite
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There isn't a factor that isn't prime or composite.
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GIVING BRAINIEST IF CORRECT!!<br> Find the area of the shaded region.
Andreyy89
Area of Shaded triangle as a whole: 136cm^2
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Area of the shaded region :
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Consider the line segment PQ with endpoints P(- 3, - 2) and Q(2, 3). Which point divides the line segment directed from P to Q i
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(0,1) point C

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8 0
3 years ago
in a test of effectiveness of garlic for lowering cholesterol, 45 subjects were treated with garlic in process tablet form. chor
leonid [27]

Answer:

Step-by-step explanation:

(a)

The sample statistic which is estimated by the population parameter is the sample mean. Moreover it is the best estimate for the population mean.From the information, it is clear that  

The sample mean is the best point estimate for the population mean. This clearly indicates that the best point estimate for the population mean is 5.1mg/dl.

(b)

From the information, it is clear that  \bar x = 5.1,\,s = 16.7,\,n = 45    

The degree of freedom is obtained below:

df = n - 1\\\\ = 45 - 1\\\\ = 44  

From “Student’s-t Distribution Table”, the required critical value is 2.704 which is lesser than the critical value.

The 99% confidence interval estimate of the mean net change in LDL cholesterol after the garlic treatment is,

{\rm{Confidence}}\,{\rm{interval}} = \bar x \pm {t_{\frac{\alpha }{2},n - 1}}\left( {\frac{S}{{\sqrt n }}} \right)\\\\ = 5.1 \pm {t_{\frac{{0.01}}{2},45 - 1}}\left( {\frac{{16.7}}{{\sqrt {45} }}} \right)\\\\ = 5.1 \pm \left( {2.704} \right)\left( {2.4895} \right)\\\\ = 5.1 \pm 6.7316\\

= \left( {5.1 - 6.7316,5.1 + 6.7316} \right)\\\\ = \left( {-1.6316,11.8316} \right)  

(c)

From the information, it is clear that the cholesterol levels were measured and identified whether the garlic treatment affects the LDL cholesterol levels or not.

It is clear that, the 99% confidence interval estimate of the mean net change in LDL cholesterol after the garlic treatment is \left( {-1.6316,11.8316} \right) . By the rejection rule for the confidence interval it is clear that the confidence interval contains 0 which clearly states that the garlic treatments do affect the LDL cholesterol levels.

3 0
3 years ago
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