Answer: 0.4 km/h
100 m = 0.1 km
15min./60min. = 0.25 hr
so, divide the total distance (100 m) by the total time (15 min)
0.1 km/0.25 hr = 0.4
Answer:
c.) 36E
Explanation:
The magnitude of the electric field is given by the expression
(1)
where k is the Coulomb's constant, q is the charge that generates the field, and d is the distance from the charge.
In this problem, we have that the magnitude of the field at a distance d is 4E, so we can rewrite the previous equation as
Now we want to determine the electric field at a distance of 
away. Substituting into (1), we find
(2)
We also know that
(3)
So combining (2) with (3), we find a relationship between the original field and the new field:
K= fx => f = k/x => 50N/100cm / 10 cm = 5/10= 0.5 N
Answer:
a. an increase in the mass on the spring.
Explanation:
An increase in the mass on the spring will increase the period of an oscillating spring mass system.
Mathematically, the period of an oscillating spring mass system is given by the formula;
T = 2π √(m/k)
Where;
T is the period.
m is the mass of the spring.
k is the spring constant.
Hence, the mass of a spring is directly proportional to the period of oscillation of the spring.
This ultimately implies that, as the mass of the spring increases, the period of oscillation will increase. Similarly, the period of oscillation will decrease with an increase in the spring constant.
I don't know what the tables you have look like but her <span>displacement</span> would be -1m
