Answer:
The frequency  = 521.59 Hz
 = 521.59 Hz
The rate at which the frequency is changing = 186.9 Hz/s 
Explanation:
Given that :
Diameter of the tank = 44 cm
Radius of the tank =  =
 = = 22 cm
 = 22 cm
Diameter of the spigot = 3.0 mm
Radius of the spigot =  =
 = = 1.5 mm
 = 1.5 mm
Diameter of the cylinder = 2.0 cm
Radius of the cylinder =  =
 =  = 1.0 cm
 = 1.0 cm
Height of the cylinder = 40 cm = 0.40 m
The height of the water in the tank from the spigot = 35 cm = 0.35 m
Velocity at the top of the tank = 0 m/s
From the question given, we need to consider that  the question talks about movement of fluid through an open-closed pipe; as such it obeys Bernoulli's Equation and the constant discharge condition.
The expression for Bernoulli's Equation is as follows:



where;
P₁ and P₂ = initial and final pressure.
v₁ and v₂ = initial and final fluid velocity
y₁ and y₂ = initial and final height 
p = density
g = acceleration due to gravity 
So, from our given parameters; let's replace 
v₁ = 0 m/s ; y₁ = 0.35 m ; y₂ = 0 m ; g = 9.8 m/s²
∴ we have:
v₂ = 
v₂ = 
v₂ = 2.61916
v₂ ≅ 2.62 m/s
Similarly, using the expression of the continuity for water flowing through the spigot into the cylinder; we have:
v₂A₂ = v₃A₃
v₂r₂² = v₃r₃²
where;
v₂r₂ = velocity of the fluid and radius at the spigot
 v₃r₃ = velocity of the fluid and radius at the cylinder

where;
v₂ = 2.62 m/s
r₂ = 1.5 mm
r₃ = 1.0 cm 
we have;
v₃ =  
 
v₃ = 0.0589 m/s
∴ velocity  of the fluid in the cylinder =  0.0589 m/s
So, in an open-closed system we are dealing with; the frequency can be calculated by using the expression;

where;
 = velocity of sound
 = velocity of sound
h = height of the fluid
v₃ = velocity  of the fluid in the cylinder 


 = 521.59 Hz
 = 521.59 Hz
∴ The frequency  = 521.59 Hz
 = 521.59 Hz
b) 
What are the rate at which the frequency is changing (Hz/s) when the cylinder has been filling for 4.0 s?
The rate at which the frequency is changing is related to the function of time (t) and as such:



where;
 (velocity of sound) = 343 m/s
 (velocity of sound) = 343 m/s
v₃ (velocity  of the fluid in the cylinder) = 0.0589 m/s
h (height of the cylinder) = 0.40 m
t (time) = 4.0 s
Substituting our values; we have ;

= 186.873
≅ 186.9 Hz/s
∴ The rate at which the frequency is changing = 186.9 Hz/s  when the cylinder has been filling for 4.0 s.