Question

Amy walks 3 m from her desk to the teacher's desk. From the teacher's desk, she then walks 4 m in the opposite direction to the classroom door. Which table correctly represents both the distance and displacement of Amy's motion?

Answer 1

Answer:

distance = 7 m

displacement = 5 m

Explanation:

distance moved by Amy is the total path length that she moved

so it is given as

$d = d_1 + d_2$

here we have

$d_1 = 3 m$

$d_2 = 4 m$

so we have

$d = 7 m$

now since both the distance that she moved is perpendicular to each other so total displacement of Amy is given as

$d = \sqrt{d_1^2 + d_2^2}$

$d = \sqrt{3^2 + 4^2} = 5 m$

Answer 2

I don't know what the tables you have look like but her displacement would be -1m